这是我的javascript代码:
function getCookie(name) {
var cookieValue = null;
if (document.cookie && document.cookie != '') {
var cookies = document.cookie.split(';');
for (var i = 0; i < cookies.length; i++) {
var cookie = jQuery.trim(cookies[i]);
// Does this cookie string begin with the name we want?
if (cookie.substring(0, name.length + 1) == (name + '=')) {
cookieValue = decodeURIComponent(cookie.substring(name.length + 1));
break;
}
}
}
return cookieValue;
};
var csrftoken = getCookie('csrftoken');
//Ajax call
function csrfSafeMethod(method) {
// these HTTP methods do not require CSRF protection
return (/^(GET|HEAD|OPTIONS|TRACE)$/.test(method));
}
$.ajaxSetup({
crossDomain: false, // obviates need for sameOrigin test
beforeSend: function(xhr, settings) {
if (!csrfSafeMethod(settings.type)) {
xhr.setRequestHeader("X-CSRFToken", csrftoken);
}
}
});
$(".color_wheel").click(function() {
$.ajax({
url:'/',
type: "POST",
data: {num : level},
});});
这是我的观点文件:
from django.shortcuts import render
from .models import Joke
# Create your views here.
def home_page(request):
return render(request, 'home.html')
def joke_page(request):
if request.POST:
num = request.POST['num']
return render(request, 'joke.html', {'joke': Joke.find_joke(num)})
如您所见,我希望Django接受AJAX调用,获取给定的数字(num)并使用它来显示新页面。问题是,它不起作用......也许我做错了,也许整件事都错了......如果你知道如何,请帮助。谢谢!
编辑:
urls.py
from django.conf.urls import url
from jokes import views
urlpatterns = [
url(r'^$', views.home_page, name='home_page'),
url(r'^(?P<joke_id>[0-9]+)/$', views.joke_page, name='joke_page'),
]
答案 0 :(得分:0)
我认为只需使用GET
请求即可完成此操作
$(".color_wheel").click(function() {
window.location.href = "/"+devel,
})
在视图中
def joke_page(request, joke_id):
return render(request, 'joke.html', {'joke': Joke.find_joke(joke_id)})