Question

我已使用下面列出的代码在uitableview中实现了搜索栏（和显示控制器）。当我在搜索文本框中输入时，我收到以下sigabrt错误：

由于未捕获的异常终止应用＆＃39; NSUnknownKeyException＆＃39;，原因：＆＃39; [valueForUndefinedKey：]：此类与密钥名称不符合键值编码。＆＃39;

我已经重新审核了我一直关注的教程并对代码进行了四倍检查，但是我找不到错误的原因，有人可以帮忙吗？

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
    if (tableView == self.searchDisplayController.searchResultsTableView) {
        return [self.searchResults count];
    } else {
        return _restaurantsInCity.count;
    }
}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    static NSString *CellIdentifier = @"RestaurantCell";
    UITableViewCell *cell = [_tableView dequeueReusableCellWithIdentifier:CellIdentifier];

    if (cell == nil) {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:CellIdentifier];
        cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator;
    }

    RestarauntEntity *currentRestaurant = nil;
    if (tableView == self.searchDisplayController.searchResultsTableView) {
        currentRestaurant = [[self.searchResults objectAtIndex:indexPath.row]];
    } else {
        currentRestaurant = [self.restaurantsInCity objectAtIndex:indexPath.row];
    }

    NSString *decodedText1 = [currentRestaurant.title stringByReplacingOccurrencesOfString:@"&#8217;" withString:@"'"];
    NSString *decodedText = [decodedText1 stringByReplacingOccurrencesOfString:@"&#038;" withString:@"&"];
    cell.textLabel.text = decodedText;
    cell.textLabel.font = [UIFont fontWithName:@"avenir" size:16.0f];
    cell.textLabel.textColor=[UIColor blackColor];
    cell.detailTextLabel.text = currentRestaurant.city;
    cell.detailTextLabel.font = [UIFont fontWithName:@"avenir" size:12.0f];
    cell.detailTextLabel.textColor=[UIColor darkGrayColor];

    return cell;
}

- (void)filterContentForSearchText:(NSString*)searchText scope:(NSString*)scope
{
    NSPredicate *resultPredicate = [NSPredicate predicateWithFormat:@"name contains[cd] %@", searchText];
    searchResults = [_restaurantsInCity filteredArrayUsingPredicate:resultPredicate];
}

-(BOOL)searchDisplayController:(UISearchDisplayController *)controller shouldReloadTableForSearchString:(NSString *)searchString
{
    [self filterContentForSearchText:searchString
                               scope:[[self.searchDisplayController.searchBar scopeButtonTitles]
                                      objectAtIndex:[self.searchDisplayController.searchBar
                                                     selectedScopeButtonIndex]]];

    return YES;
}

Answer 1

试试这个

如果您在按钮上创建了任何不再存在的插座或操作，则会发生这种情况。检查所有操作和插座。转到您的故事板并右键单击viewcontroller的黄色标志，并删除带有黄色标记的所有操作和插座。

enter image description here

希望它有所帮助。

libc++abi.dylib: terminating with uncaught exception of type NSException (lldb)

尝试这个答案希望它有所帮助。

Answer 2

如果您无法调试当前代码，您可以在UITextField的帮助下实现搜索栏功能。只需在UITableView上方放置一个UITextField而不是搜索栏，然后设置委托。确保使用数据对象类的正确变量名称。我在这里编写代码，请告诉我这是否有帮助

-(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section{

if (isFromSearchResult) // BOOL to determine is from search result or not
{
    return [searchResults count];
}
else
{
    return myAppDelegate.offersArr.count;
}

}

- （UITableViewCell *）tableView：（UITableView *）tableView cellForRowAtIndexPath：（NSIndexPath *）indexPath {

customCell = (offersCustomTableViewCell*)[tableView dequeueReusableCellWithIdentifier:@"Cell"];

if(isFromSearchResult)
{
    dataObj = [searchResults objectAtIndex:indexPath.row]; //dataObj is object of NSObject data class
} else
{
    dataObj = [myAppDelegate.offersArr objectAtIndex:indexPath.row];
}

customCell.LblOffer.text = [dataObj.OfferTitle uppercaseString];

NSString *validity = @"VALID TILL: "; // dataObj.ValidTime;
customCell.LblValid.text = [validity stringByAppendingString:dataObj.ValidTime];

return customCell;

}

- （void）filterContentForSearchText：（NSString *）searchText范围：（NSString *）scope { //这里搜索三个字段 - 标题，内容和地址

NSPredicate *predicateOfferTitle = [NSPredicate predicateWithFormat:@"OfferTitle contains[cd] %@", searchText];
NSPredicate *predicateOfferContent = [NSPredicate predicateWithFormat:@"OfferContent contains[cd] %@", searchText];
NSPredicate *predicateAddress = [NSPredicate predicateWithFormat:@"Address contains[cd] %@", searchText];

NSArray *subPredicates = [NSArray arrayWithObjects:predicateOfferTitle, predicateOfferContent,predicateAddress, nil];
NSPredicate *orPredicate = [NSCompoundPredicate orPredicateWithSubpredicates:subPredicates];
searchResults = [myAppDelegate.offersArr filteredArrayUsingPredicate:orPredicate];
//NSLog(@"%@", searchResults);

}

- （BOOL）textField：（UITextField *）textField shouldChangeCharactersInRange：（NSRange）range replacementString：（NSString *）string {

NSString *value = [textField.text stringByReplacingCharactersInRange:range withString:string];
//NSLog(@"value: %@", value);
if (![value isEqualToString:@""]) {
    [self filterContentForSearchText:value scope:[[self.searchDisplayController.searchBar scopeButtonTitles] objectAtIndex:[self.searchDisplayController.searchBar selectedScopeButtonIndex]]];

    isFromSearchResult=YES;
}
else
{
    isFromSearchResult=NO;
}

[offersTable reloadData];
return true;

}

UitableView搜索文本Sigbart错误 - ios

2 个答案: