我正在尝试将一些信息插入数据库,但它无法正常工作。以下是我的代码:
$sql4 = "INSERT INTO favorites (posted-date,posted-time,posted-
datetime,journalid, by) VALUES ('test','test','test','test','test')";
答案 0 :(得分:0)
尝试
SELECT A.cs_id,
A.class,
B.sec_id,
B.cs_id,
B.cs_name,
C.stud_id,
C.stud_class,
C.stud_section,
C.stud_adm_no,
C.stud_full_name
FROM class_section AS A
INNER JOIN section_name as B ON A.cs_id=b.cs_id
INNER JOIN student_detail as c ON C.stud_class=B.sec_id WHERE A.cs_id=1
同时检查您是否正确连接数据库。
如果你的表和所有字段的类型正确且存在,请查看它们。
答案 1 :(得分:0)
终于奏效了。我仍然没有弄清楚错误的原因,但以下是工作代码:
$ sql4 =" INSERT INTO favorites
(
id
,
posted-date
,
posted-time
,
posted-datetime
,
journalid
,
by
)
价值观(
NULL,' test',' test',' test',' test',' test'
)&#34 ;;