Question

我试图在两个单独的表中搜索特定值的COUNT并从函数返回它。

  FUNCTION check_parts
    (p_partno         IN  VARCHAR2)
    RETURN NUMBER
  IS
    out_exists  NUMBER;
    sub_exists  NUMBER;
  BEGIN

    SELECT COUNT(*) INTO out_exists
    FROM outline_pn op
    WHERE op.outline_pn = p_partno
    UNION ALL
    SELECT COUNT(*)
    FROM sub_pn sp
    WHERE sp.sub_assy_pn = p_partno;
--      SELECT (SELECT COUNT(*) AS out_exists
--              FROM outline_pn op
--              WHERE op.outline_pn = p_partno) AS out_exists,
--              (SELECT COUNT(*) AS sub_exists
--              FROM sub_pn sp
--              WHERE sp.sub_assy_pn = p_partno) AS sub_exists


      RETURN (out_exists + sub_exists);
  END check_parts;

起初，我天真地认为两个COUNT(*)个问题会起作用......它没有。

如何对两个单独的COUNT查询的值求和并返回结果？

感谢任何帮助。

Answer 1

我没有找到不使用两个单独查询的理由。然后你可以返回两者的总和。你可以简单地写下这样的东西：

FUNCTION check_parts   
(p_partno         IN  VARCHAR2)
RETURN NUMBER
IS
out_exists  NUMBER;
sub_exists  NUMBER;
BEGIN

SELECT COUNT(*) INTO out_exists
FROM outline_pn op
WHERE op.outline_pn = p_partno;

SELECT COUNT(*) INTO sub_exits
FROM sub_pn sp
WHERE sp.sub_assy_pn = p_partno;


RETURN (out_exists + sub_exists);
END check_parts;

Answer 2

如果你仍想在一个查询中使用它，这里是选项

  create FUNCTION check_parts
    (p_partno         IN  VARCHAR2)
    RETURN NUMBER
  IS
    sum_exists  NUMBER;
  BEGIN

  select count(1) into sum_exists from (
    SELECT outline_pn
    FROM outline_pn op
    WHERE op.outline_pn = p_partno
    UNION ALL
    SELECT sub_assy_pn
    FROM sub_pn sp
    WHERE sp.sub_assy_pn = p_partno);


      RETURN (sum_exists);
  END check_parts;

返回两个单独的表PL / SQL的计数总和

2 个答案: