Question

我有一张包含以下结构的表格：

    ID   EmployeeType   Name
    1     Contract      John, Baxter
    2     Contract      Will, Smith
    3     Full          Josh, Stevens
    4     Full          Sitar, Zhang

我需要做的就是转动它，以便得到以下输出：

      Contract_Employee   FullTime_Employee
      John, Baxter        Josh, Stevens
      Will,Smith          Sitar, Zhang

知道如何在一个查询中执行此操作吗？

Answer 1

这是一个有趣的请求。这是我将如何做到的：（基本上，只需将假密钥导出到＆＃34;加入＆＃34;对于两个派生表，对于承包商，一个为员工）

    CREATE TABLE #Table1
        ([ID] int, [EmployeeType] varchar(8), [Name] varchar(13))
    ;

    INSERT INTO #Table1
        ([ID], [EmployeeType], [Name])
    VALUES
        (1, 'Contract', 'John, Baxter'),
        (2, 'Contract', 'Will, Smith'),
        (3, 'Full', 'Josh, Stevens'),
        (4, 'Full', 'Sitar, Zhang'),
        (5, 'Full','Bob, Bob'),
        (6, 'Contract','Bob, Bob')
    ;


    select
    c.name as ContractEmployee,
    f.name as FullTime_Employee
    from
    (
    select
    row_number() over (order by id) as RN,
    name
    from
    #table1
    where 
    employeetype = 'Contract'
      ) c
    full join (
    select
    row_number() over (order by id) as RN,
    name
    from
    #table1
    where 
    employeetype = 'Full'
    ) f
    on 
c.name = f.name OR
c.rn = f.rn

Answer 2

这样做的一种方法是使用聚合：

select max(case when employeetype = 'Contract' then Name end) as ContractEmployees,
       max(case when employeetype = 'Full' then Name end) as FullEmployees       
from (select t.*,
             row_number() over (partition by employeetype order by id) as seqnum
      from table t
     ) t
group by seqnum;

自我加入sql没有聚合

2 个答案: