我有一个data.frame CLI_CAP_X_PROD_AG:
FAMILIA_PRD NUM_CLI CAPITAL_SOL PART_CAP_PER ATRASADA ATR_PER
A 536 2616925 33.62 467830 17.88
B 151 1613035 20.72 268223 16.63
当我尝试使用data.frame的名称保存文件时出现错误:
print(temp,type = "html", include.rownames = FALSE, file = paste(CLI_CAP_X_PROD_AG,"_tab.html", sep=""))
因为R读取了CLI_CAP_X_PROD_AG的元素。
非常感谢任何帮助!
答案 0 :(得分:0)
您应该将xtables存储在命名列表中并遍历列表。演示:
library('xtable');
li <- list(t1=xtable(data.frame(a=letters[1:3],b=1:3)),t2=xtable(data.frame(a=letters[4:6],b=4:6)));
names(li);
## [1] "t1" "t2"
li;
## $t1
## % latex table generated in R 3.1.3 by xtable 1.7-4 package
## % Fri Jun 19 13:48:30 2015
## \begin{table}[ht]
## \centering
## \begin{tabular}{rlr}
## \hline
## & a & b \\
## \hline
## 1 & a & 1 \\
## 2 & b & 2 \\
## 3 & c & 3 \\
## \hline
## \end{tabular}
## \end{table}
##
## $t2
## % latex table generated in R 3.1.3 by xtable 1.7-4 package
## % Fri Jun 19 13:48:30 2015
## \begin{table}[ht]
## \centering
## \begin{tabular}{rlr}
## \hline
## & a & b \\
## \hline
## 1 & d & 4 \\
## 2 & e & 5 \\
## 3 & f & 6 \\
## \hline
## \end{tabular}
## \end{table}
##
for (n in names(li)) print(li[[n]],type='html',include.rownames=F,file=paste0(n,'_tab.html'));
file.show('t1_tab.html',pager='cat');
## <!-- html table generated in R 3.1.3 by xtable 1.7-4 package -->
## <!-- Fri Jun 19 13:48:34 2015 -->
## <table border=1>
## <tr> <th> a </th> <th> b </th> </tr>
## <tr> <td> a </td> <td align="right"> 1 </td> </tr>
## <tr> <td> b </td> <td align="right"> 2 </td> </tr>
## <tr> <td> c </td> <td align="right"> 3 </td> </tr>
## </table>
##
file.show('t2_tab.html',pager='cat');
## <!-- html table generated in R 3.1.3 by xtable 1.7-4 package -->
## <!-- Fri Jun 19 13:48:34 2015 -->
## <table border=1>
## <tr> <th> a </th> <th> b </th> </tr>
## <tr> <td> d </td> <td align="right"> 4 </td> </tr>
## <tr> <td> e </td> <td align="right"> 5 </td> </tr>
## <tr> <td> f </td> <td align="right"> 6 </td> </tr>
## </table>
##