Question

我尝试接受localhost：8000 /上传文件并遇到此问题

未绑定方法upload_file（）必须使用Upload instance作为第一个参数调用（改为获取WSGIRequest实例）

urls.py

from django.conf.urls import include, url
from django.contrib import admin

from upload.views import Upload


urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),
    url(r'^upload/$', Upload.upload_file),
    url(r'^thanks/$', Upload.thanks),
]

views.py

from django.http import HttpResponse
from django.template import RequestContext

from django.shortcuts import render_to_response
from upload.forms import FileForm

from upload.models import upFile

class Upload():

    def upload_file(request):
        if request.method == "POST":
            form = FileForm(request.POST, request.FILES)
            if form.is_valid():
                form.save()
                return HttpResponseRedirect('thanks')
        else:
            form = FileForm()

        return render_to_response('temp1.html', {'form': form}, context_instance = RequestContext(request))

    def thanks(request):
        return render_to_response('temp2.html')

Answer 1

您的视图不是从基于Django类的视图继承的：https://docs.djangoproject.com/en/1.8/topics/class-based-views/intro/

from django.views.generic import View


class Upload(View):
    def upload_file(self, request):
        if request.method == "POST":
            form = FileForm(request.POST, request.FILES)
            if form.is_valid():
                form.save()
                return HttpResponseRedirect('thanks')
        else:
            form = FileForm()

        return render_to_response('temp1.html', {'form': form}, context_instance = RequestContext(request))

    def thanks(self, request):
        return render_to_response('temp2.html')

您需要继承其中一个视图类，否则Django会将您的视图视为普通类，这就是您收到该错误的原因。

您还需要调整urls.py：

urlpatterns = [
    url(r'^upload/', Upload.as_view()),
]

在查看了文档和vie的结构之后，我不确定您是否正在为基于类的视图正确构建视图。您可能需要更多地阅读文档并相应地调整您的结构。

我相信你会想要一些看起来更像这样的东西：

class Upload(View):
    def get(self, request):
        form = FileForm()
        return render_to_response('temp1.html', {'form': form}, context_instance = RequestContext(request))

    def post(self, request):
        form = FileForm(request.POST, request.FILES)
        if form.is_valid():
            form.save()
            return HttpResponseRedirect('thanks')
        else:
            return render_to_response('temp2.html')

Answer 2

我不明白为什么你有上传课程。 Python不是Java，没有必要把所有东西都放到类中。将upload_file和thanks放在模块级别，并直接在网址模式中引用它们。

Django的。网址中的未绑定方法

2 个答案: