Question

如何将以下查询转换为带连接的查询？

我尝试了第二个查询，但那给了我？加倍？并没有合理的结果。

提前谢谢！

工作（但很尴尬，不使用连接）：

SELECT score_cards.id, score_cards.start_time, score_cards.end_time, users.name AS user_name, holes.sort, hole_scores.score 
FROM
score_card_user AS score_card_user,
score_cards AS score_cards,
score_card_hole_score AS score_card_hole_score,
hole_scores AS hole_scores,
holes AS holes,
courses AS courses,
users AS users
WHERE
score_card_user.sc_id = score_cards.id
AND score_card_hole_score.sc_id = score_cards.id
AND score_card_hole_score.hs_id = hole_scores.id
AND score_cards.course_id = courses.id
AND hole_scores.user_id = users.id
AND holes.id = hole_scores.hole_id
AND score_card_user.user_id = users.id
ORDER BY score_cards.id ASC, user_name ASC, holes.sort ASC

不起作用：

SELECT score_cards.id, score_cards.start_time, score_cards.end_time, users.name AS user_name, holes.sort, hole_scores.score
FROM
score_cards
INNER JOIN score_card_user
  ON score_cards.id = score_card_user.sc_id
INNER JOIN score_card_hole_score
  ON score_cards.id = score_card_hole_score.sc_id
INNER JOIN hole_scores
  ON hole_scores.id = score_card_hole_score.hs_id
INNER JOIN holes
  ON holes.id = hole_scores.hole_id
INNER JOIN courses
  ON courses.id = score_cards.course_id
INNER JOIN users
  ON users.id = score_card_user.user_id
ORDER BY score_cards.id ASC, user_name ASC, holes.sort ASC

Answer 1

似乎你错过了一个条件：hole_scores.user_id = users.id你应该添加

...
INNER JOIN users
  ON users.id = score_card_user.user_id AND hole_scores.user_id = users.id
....

Answer 2

您混合了某些表的顺序并忘记了其中一个条件。在这里，试试这个：

SELECT score_cards.id, score_cards.start_time, score_cards.end_time, users.name AS user_name, holes.sort, hole_scores.score
FROM
score_cards
INNER JOIN score_card_user
  ON score_cards.id = score_card_user.sc_id
INNER JOIN score_card_hole_score
  ON score_cards.id = score_card_hole_score.sc_id
INNER JOIN hole_scores
  ON hole_scores.id = score_card_hole_score.hs_id 
INNER JOIN courses
  ON courses.id = score_cards.course_id
INNER JOIN holes
  ON holes.id = hole_scores.hole_id
INNER JOIN users
  ON users.id = score_card_user.user_id 
  and users.id = hole_scores.user_id     
ORDER BY score_cards.id ASC, user_name ASC, holes.sort ASC

还有一件事：表别名可以避免长时间输入。给他们起了同样的名字毫无意义。通常人们会做类似

的事情

select 
    whatever
from 
    table as t,
    other_table as ot
where
    ot.t_id = t.id

将查询转换为使用连接

2 个答案: