Question

我的公式如下：

Conversion = Settled / (Settled + Cancelled)

如何在LINQ语句中执行此操作？

这是我的代码：

WIP = g.Where(v => v.StatusCategoryID == 40).Sum(c => c.Amount) ?? 0,
Settled = g.Where(v => v.StatusCategoryID == 11).Sum(c => c.Amount) ?? 0,
Cancelled = g.Where(v => v.StatusCategoryID == 10).Sum(c => c.Amount) ?? 0,

Answer 1

您可以使用Aggregate尝试这样的事情（虽然感觉有点滥用）：

var agg = g.Aggregate(new { wip = 0, settled = 0, cancelled = 0 }, (a, curr) => 
{
    return new 
    { 
        wip = a.wip + a.StatusCategoryID == 40 ? curr.Amount : 0, 
        settled = a.settled + a.StatusCategoryID == 11? curr.Amount : 0, 
        cancelled = a.cancelled + a.StatusCategoryID == 10? curr.Amount : 0, 
    };
});

然后你可以：

var Conversion = agg.settled / (agg.settled + agg.cancelled);

和

var WIP = agg.wip;

这里的优势在于您只需在一个循环中对所有三个类别进行求和。我不确定我发现比使用foreach循环要好得多。

如何在LINQ中执行此公式？

1 个答案: