我用css元素(“.cursory”)替换了我的鼠标指针。现在它是一个小绿圈。我已经设置了一个定时器,可以检测鼠标何时空闲2秒钟。我想在鼠标空闲时将绿色更改为红色,但我无法弄清楚如何获取(“粗略”).css(...)工作。下面是我的代码,问题.css()在goInactive函数中:
<!DOCTYPE html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script><!--this is the jQuery document link-->
<script>
// this is where jQuery functions go
//TESTING IF THE UI IS IDLE
var TimeoutID;
function inputdetect() {
// attaches event handler to specified event
// takes event as string, function to run, and optional boolean
// to indicate when the event propogates
// these are false, so events "bubble up"
this.addEventListener("mousemove",resetTimer,false);
this.addEventListener("mousedown",resetTimer,false);
this.addEventListener("mousewheel",resetTimer,false);
this.addEventListener("keypress",resetTimer,false);
this.addEventListener("touchmove",resetTimer,false);
this.addEventListener("DOMmousescroll",resetTimer,false);
this.addEventListener("MSpointermove",resetTimer,false);
startTimer();
}
inputdetect();
function startTimer() {
//waits two seconds before calling inactive
TimeoutID = window.setTimeout(goInactive,2000); // does it need to take the window variable??
}
function resetTimer(e) {
window.clearTimeout(TimeoutID);
goActive();
}
function goActive() {
//what happens when the UI is not idle
$('p').text("The UI is not idle.");
startTimer();
}
function goInactive() {
$('p').text("The UI is idle.");
// REPLACING CURSOR WHEN UI IS IDLE
//this part won't work
$('cursory').css("background-color","red");
}
// THIS changes the pointer to a css element
$(document).ready(function() {
$(document).on('mousemove', function(e) {
$('.cursory').css({
left: e.pageX,
top: e.pageY
});
});
});
</script>
</head>
<style>
/*this is where CSS styling goes*/
html {
cursor: none;
}
.cursory {
height: 10px;
width: 10px;
border-radius: 100%;
background-color: green;
position: relative;
}
</style>
<body>
<div class = "cursory"></div>
<!--this is where the HTML will go*/-->
<p>hello</p>
答案 0 :(得分:2)
cursory
是元素的类,使用类选择器.className
$('.cursory').css("background-color","red");
答案 1 :(得分:-1)
可能缺少问题“。” ......
$('.cursory').css("background-color","red");
关于选择器的一篇小文章: http://www.w3schools.com/jquery/jquery_ref_selectors.asp
答案 2 :(得分:-1)
根据您上面的代码,看起来您没有在jQuery调用中使用适当的CSS选择器。
更改此
$('cursory').css("background-color","red");
到
$('.cursory').css("background-color","red");