Question

我正在开发一个连接到mysql数据库并使用用户和密码登录的应用程序，这很有效，现在我需要从该用户获取其他数据并将其显示在标签中。如何在表格中从该用户获取此数据并将其显示在标签中？

我的PHP文件：

<?php
// Ghalia ALrajban
// 21 Dec 2011

if (isset($_GET["email"])  && isset($_GET["senha"]) ){
                $email = $_GET["email"];
                $senha = $_GET["senha"];
                $result = login( $email, $senha);
                echo $result;
                }

function makeSqlConnection()
{
$DB_HostName = "***.com";
$DB_Name = "***gou";
$DB_User = "***gou";
$DB_Pass = "***";

    $con = mysql_connect($DB_HostName,$DB_User,$DB_Pass) or die(mysql_error()); 

        mysql_select_db($DB_Name,$con) or die(mysql_error()); 

    return $con;
}

function disconnectSqlConnection($con)
{
    mysql_close($con);
}

function login($email, $senha)
{
    //require (FILE);
    $con = makeSqlConnection();

    $sql = "select * from usuario_log  where email = '$email' and senha = '$senha';";
    $res = mysql_query($sql,$con) or die(mysql_error());

    $res1 = mysql_num_rows($res);

    disconnectSqlConnection($con);

     if ($res1 != 0) {
        return 1;
    }else{
        return 0;
    }// end else


}// end of Function 

?>

我的.m文件中的登录按钮：

    #pragma mark - BOTAO LOGIN
- (IBAction)loginButton:(id)sender {
    // Verificar e informar se os dados estao em branco.
    if([emailTextField.text isEqualToString:@""] || [senhaTextField.text isEqualToString:@""]) {
        UIAlertView *errorbranco = [[UIAlertView alloc] initWithTitle:@"Erro" message:@"Preencha todos os campos" delegate:self cancelButtonTitle:@"OK" otherButtonTitles: nil];
        [errorbranco show];
    }

    //Verificar informacoes no banco de dados
    else{
        NSString *strURL = [NSString stringWithFormat:@"http://peggou.com.br/login.php?email=%@&senha=%@", emailTextField.text, senhaTextField.text];
        NSData *dataURL = [NSData dataWithContentsOfURL:[NSURL URLWithString:strURL]];
        NSString *strResult = [[NSString alloc] initWithData:dataURL encoding:NSUTF8StringEncoding];

        //Informacoes Corretas
        if ([strResult isEqualToString:@"1"]) {
            [self performSegueWithIdentifier:@"entrou" sender:self];
        }
        //Informacoes Incorretas
        else{
            UIAlertView *error = [[UIAlertView alloc] initWithTitle:@"Erro" message:@"e-mail ou senha invalidos" delegate:self cancelButtonTitle:@"OK" otherButtonTitles: nil];
            [error show];
        }
    }
}

Answer 1

您可以使用dataWithContentsOfURL并返回json结构，如前面的答案中所述：JSON encode MySQL results

使用NSJSONSerialization将其转换回ios部分。

但请记住，尝试同时显示＆gt; 100个表行是不好的，所以请使用分页（SQL：limit PN*PS+1,PS，其中PN =页码，PS =页面大小），以获得自己的理智

如何在mysql的标签中显示用户数据？ Xcode中

1 个答案: