Question

我想将选定的单选按钮值插入数据库。只是＆＃34;是＆＃34;或＆＃34;不＆＃34;。如果有人能给我一个想法，那将是一个很大的帮助。我正在使用codeigniter框架。提前谢谢。

模型

function add_reservation($reservation_model) {
        return $this->db->insert('reservations', $reservation_model);
    }

控制器

function add_reservation() {
        $reservation_model = new Reservation_model();
        $reservation_service = new Reservation_service();

        $reservation_model->set_date_cal(trim($this->input->post('date', TRUE)));
        $reservation_model->set_date(strtotime($this->input->post('date', TRUE)));
        $reservation_model->set_title(trim($this->input->post('selected_hall', TRUE)));
        $reservation_model->set_type(trim($this->input->post('selected_time', TRUE)));
        $reservation_model->set_description(trim($this->input->post('name', TRUE)));
        $reservation_model->set_advanced_payment_status(trim($this->input->post('advanned_paid_radio_button', TRUE)));
        $reservation_model->set_paid_amount(trim($this->input->post('paid_amount', TRUE)));
        $reservation_model->set_fax(trim($this->input->post('fax', TRUE)));
        $reservation_model->set_telephone_number(trim($this->input->post('telephone', TRUE)));
        $reservation_model->set_address(trim($this->input->post('address', TRUE)));
        $reservation_model->set_menu_no(trim($this->input->post('selected_menu_number', TRUE)));
        $reservation_model->set_menu_price_per_plate(trim($this->input->post('menu_price', TRUE)));
        $reservation_model->set_is_deleted('0');

        $this->db->last_query();

        echo $reservation_service->add_reservation($reservation_model);
    }

查看

<label for="advanced_paid">Advanced paid</label>                        
                        <div id="advanned_paid_radio_button">                           
                            <input type="radio" onclick="myFunction()" name="optionsRadios" id="yes" value="yes"> Yes
                            <input type="radio" onclick="myNoFunction()" name="optionsRadios" id="no" value="no"> No

                        </div>

在javascript中我有这个。

                 function myFunction() {                               

                       if ($('input[id="yes').is(':checked')) {
                            $('div[id="paid"]').show();
                        }
                        if ($('input[id="no"]').is(':checked')) {
                            $('div[id="paid"]').hide();
                        }

                    }

                    function myNoFunction() {
                        if ($('input[id="no"]').is(':checked')) {
                            $('div[id="paid"]').hide();
                        }
                    }

Answer 1

要确定单选按钮的值，您应该通过.val()

获取它

并将其存储在变量

中

if ($('input[id="yes').is(':checked')) {
$('div[id="paid"]').show();
var value = $(this).val();
//your ajax call shall be here
}

if ($('input[id="no"]').is(':checked')) {
$('div[id="paid"]').hide();
var value = $(this).val();
//your ajax call shall be here 
}

然后要在数据库中更新它，您应该对控制器进行jquery-ajax调用，并在数据库中插入/更新值。

注意：如果您只想更新数据库中的Yes或No，您甚至不需要拥有函数myFunction或{ {1}}。

你可以在改变事件中使用它

Answer 2

我认为问题是，您发布的id单选按钮advanned_paid_radio_button哪个错误，您需要发布name='optionsRadios'的广播而不是id {{ 1}} advanned_paid_radio_button。

controller

如何将单选按钮值插入数据库？

2 个答案: