Question

尝试创建一个生成以下用户列表的查询：

A。）登录用户尚未关注

B中。）登录用户尚未查看和跳过（FOLLOWER_SWIPES表）

以下是我的查询，由于某种原因，它仍然向用户显示过去登录用户已跳过：

SELECT u.uid, u.full_name, u.bio, u.thumb_img, u.college, u.HEADER_IMG
FROM users AS u
WHERE u.uid <>'$uid'
AND u.uid <> ANY(

SELECT FOLLOWING_UID_FK
FROM FOLLOWERS
WHERE UID_FK='$uid'
)
AND u.uid <> ANY(
SELECT SWIPPED_UID_FK
FROM FOLLOWER_SWIPES
WHERE UID_FK =$uid
)
AND u.college_id='$college'
ORDER BY u.last_feed_load DESC
LIMIT 0 , 30

Answer 1

条件：

AND u.uid <> ANY(
SELECT SWIPPED_UID_FK
FROM FOLLOWER_SWIPES
WHERE UID_FK =$uid
)

不是一个非常严格的条件。尝试使用ALL代替ANY：

AND u.uid <> ALL (SELECT SWIPPED_UID_FK
                  FROM FOLLOWER_SWIPES
                  WHERE UID_FK = $uid
                 )

或使用等效物：

AND u.uid NOT IN (SELECT SWIPPED_UID_FK
                  FROM FOLLOWER_SWIPES
                  WHERE UID_FK = $uid
                 )

Doulbe＆lt;＆gt;任何查询无法处理第二个＆lt;＆gt; ANY

1 个答案: