Question

我正在尝试在SQL Server中生成一个如下所示的表：

Name     | Mon | Tue | Wed | Thu | Fri | Sat | Sun | Total
Product1 | 2   | 0   | 1   | 0   | 1   | 0   | 0   | 4
Product2 | 2   | 1   | 0   | 1   | 0   | 0   | 0   | 4
Product3 | 1   | 0   | 0   | 0   | 0   | 0   | 0   | 1

我的数据目前位于以下三个表格中：

ProductName
ID | Name             
1  | Product1    
2  | Product2   
3  | Product3      

ProductSelection
PID | CID
1   | 1
1   | 2
1   | 3
2   | 1
2   | 2
3   | 2
4   | 1
5   | 2
6   | 1

ProductOrder 
ID | Name     | SubmitDate
1  | John Doe | 6/15/2015       
2  | Jane Doe | 6/15/2015 
3  | Sam Doe  | 6/16/2015 
4  | Mark Doe | 6/17/2015 
5  | Bob Doe  | 6/18/2015
6  | Adam Doe | 6/19/2015

现在我知道我需要使用类似于此的PIVOT：

PIVOT (COUNT(Name) FOR [Day] IN (Mon, Tue, Wed, Thu, Fri, Sat, Sun)) AS PivotTable

但我正在努力将其余的查询放在一起。我不知道如何获得总数，也许是内部加入？非常感谢任何帮助。

Answer 1

除了使用PIVOT之外，您还可以尝试使用条件聚合：

SQL Fiddle

SELECT
    Name    = pn.Name,  
    [Mon]   = SUM(CASE WHEN DATENAME(WEEKDAY, po.SubmitDate) = 'Monday' THEN 1 ELSE 0 END),
    [Tue]   = SUM(CASE WHEN DATENAME(WEEKDAY, po.SubmitDate) = 'Tuesday' THEN 1 ELSE 0 END),
    [Wed]   = SUM(CASE WHEN DATENAME(WEEKDAY, po.SubmitDate) = 'Wednesday' THEN 1 ELSE 0 END),
    [Thu]   = SUM(CASE WHEN DATENAME(WEEKDAY, po.SubmitDate) = 'Thursday' THEN 1 ELSE 0 END),
    [Fri]   = SUM(CASE WHEN DATENAME(WEEKDAY, po.SubmitDate) = 'Friday' THEN 1 ELSE 0 END),
    [Sat]   = SUM(CASE WHEN DATENAME(WEEKDAY, po.SubmitDate) = 'Saturday' THEN 1 ELSE 0 END),
    [Sun]   = SUM(CASE WHEN DATENAME(WEEKDAY, po.SubmitDate) = 'Sunday' THEN 1 ELSE 0 END),
    [Total] = COUNT(*)
FROM ProductOrder po
INNER JOIN ProductSelection ps 
    ON ps.PID = po.ID
INNER JOIN ProductName pn
    ON pn.ID = ps.CID
GROUP BY pn.Name

<强> RESULT

|     Name | Mon | Tue | Wed | Thu | Fri | Sat | Sun | Total |
|----------|-----|-----|-----|-----|-----|-----|-----|-------|
| Product1 |   2 |   0 |   1 |   0 |   1 |   0 |   0 |     4 |
| Product2 |   2 |   1 |   0 |   1 |   0 |   0 |   0 |     4 |
| Product3 |   1 |   0 |   0 |   0 |   0 |   0 |   0 |     1 |

Answer 2

试试这个：

$("#divid").on("click", ".tableid", function(){

  alert($(this).find('td:first').text());

});

您将获得每周产品销售计数的所有计数

创建查询以显示一周中每天销售的产品数量

2 个答案: