Question

所以我是Linux的新手，我们的导师给了我们这个任务，它非常简单，但我还没有能够为我的员工代码创建一个独特的专栏＆＃39; （我们需要这个以避免重复代码）我尝试了以下两种方法

方法1

    echo "Enter an Employee Code:
 read code
    if [$code uniq -u]
 then
    echo "Enter surname"
 read surname
    echo "Enter Other names"
 read other_names
    echo "Choose Gender"
    echo "f Female  m male"
 read gender
    case $gender in

         f) Female;;
         m) Male;;
         *) echo" that was not one of the choices"
           esac
    echo " Enter DOB"
 read dob
    echo "Enter Phone Number"
 read phone_num
    echo "$code   $surname   $other_names   $gender   $dob" >> details

否则 echo＆＃34;重复员工代码＆＃34; 网络

方法2

     echo "Enter an Employee Code:
 read code
     while [ $code -ne $code ]
 do
     echo "Enter surname"
 read surname
     echo "Enter Other names"
 read other_names
     echo "Choose Gender"
     echo "f Female  m male"
 read gender
    case $gender in
          f) Female;;
          m) Male;;
          *) echo" that was not one of the choices"
            esac
   echo " Enter DOB"
 read dob
   echo "Enter Phone Number"
 read phone_num
   echo "$code   $surname   $other_names   $gender   $dob" >> details

否则 echo＆＃34;重复员工代码＆＃34;

完成

有人可以帮忙吗？ 方法1 无法识别＆＃34; uniq＆＃34;约束，而方法2 保持不停增量。非常感谢提前:)）

在Linux中创建一个唯一的列（更像是一个sql主键？）

0 个答案: