Question

我正在尝试编写一个程序来查找句子中的字母总数。我想知道为什么我的程序错了。这就是我试过的：

words = ["hi", "how", "are", "you"]

alphabet = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]

y = 0

for i in words:
    for x in alphabet:
        n = words.count(x)
        y = y + n
print (y)

这个程序只返回4个零。

从我的角度来看，该程序应该像这样运行：在循环的第一次运行中，i =＆＃34; hi＆＃34;和x =＆＃34; a＆＃34; 。＆＃34; a＆＃34;的数量存储在变量n中，然后存储在变量y中。然后x取值＆＃34; b＆＃34;，＆＃34; c＆＃34;等等，直到它贯穿整个字母表。然后重复下一件事，直到我转到第二个单词。

Answer 1

您的计划无效的原因是 - 您正在将words与每个单词i进行迭代，但在内循环中，您正在执行words.count()而不是i.count() }。

这就是你的for循环应该是这样的 -

for i in words:
    for x in alphabet:
        n = i.count(x)
        y = y + n
print (y)

Answer 2

更改

n = words.count(x)

到

n = i.count(x)

诀窍。

<强>原因

您说i是每次迭代中的一个单词。因此，您必须使用i.count(x)来计算x中i的数量

Answer 3

我认为你应该使用n = i.count(x)，而不是＆＃34; n = words.count（x）＆＃34;

words = ["hi", "how", "are", "you"]

alphabet = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]

y = 0

for i in words:
    for x in alphabet:
        n = i.count(x)
        y = y + n

print (y)

输出

Answer 4

sentence = "hi how are you"
count = sum(1 for c in sentence if c.isalpha())

找一个句子中的字母数？

4 个答案: