Question

我有一个过滤表的表单，我希望表单条目可以构建sqlalchemy语句。

因为我有选项＆＃34;无过滤器＆＃34;，我不能让表单字段进入过滤器（此处为＆＃39;表单字段＆＃39;）。但是必须有一个比做每个排列更好的方法，比如

AT= list(set([h.assigned for h in models.Request.query.all()]))
AT.append('No Filter')
form.assigned.choices=zip(AT,AT)
requestlist= models.Request.query.all() 
if form.validate_on_submit():

    if form.status.data=='No Filter' and form.assigned.data=='No Filter' and form.requestor.data=='No Filter':
            requestlist= models.Request.query.all() 
    elif form.status.data != 'No Filter' and form.assigned.data=='No Filter' and form.requestor.data=='No Filter':
        requestlist = db.session.query(models.Request).filter(models.Request.status.like(form.status.data)).all()
    elif form.status.data == 'No Filter' and form.assigned.data!='No Filter' and form.requestor.data=='No Filter':
        requestlist = db.session.query(models.Request).filter(models.Request.assigned.like(form.assigned.data)).all()
    elif form.status.data == 'No Filter' and form.assigned.data=='No Filter' and form.requestor.data!='No Filter':
        requestlist = db.session.query(models.Request).filter(models.Request.requestedBy.like(form.requestor.data)).all()
    elif form.status.data != 'No Filter' and form.assigned.data=='No Filter' and form.requestor.data!='No Filter':
        requestlist = db.session.query(models.Request).filter(models.Request.requestedBy.like(form.requestor.data))\
        .filter(models.Request.status.like(form.status.data)).all()
    elif form.status.data == 'No Filter' and form.assigned.data !='No Filter' and form.requestor.data!='No Filter':
        requestlist = db.session.query(models.Request).filter(models.Request.requestedBy.like(form.requestor.data))\
        .filter(models.Request.assigned.like(form.assigned.data)).all()
    elif form.status.data != 'No Filter' and form.assigned.data !='No Filter' and form.requestor.data =='No Filter':
        requestlist = db.session.query(models.Request).filter(models.Request.status.like(form.status.data))\
        .filter(models.Request.assigned.like(form.assigned.data)).all()
    elif form.status.data != 'No Filter' and form.assigned.data !='No Filter' and form.requestor.data !='No Filter':
        requestlist = db.session.query(models.Request).filter(models.Request.status.like(form.status.data))\
        .filter(models.Request.requestedBy.like(form.requestor.data))\
        .filter(models.Request.assigned.like(form.assigned.data)).all()

Answer 1

您可以一个接一个地添加多个filter(...)条款：

if form.validate_on_submit():
    requestlist = models.Request.query

    if form.status.data != 'No Filter':
        requestlist = requestlist.filter(models.Request.status.like(form.status.data))

    if form.assigned.data != 'No Filter':
        requestlist = requestlist.filter(models.Request.assigned.like(form.assigned.data))

    if form.requestor.data != 'No Filter':
        requestlist = requestlist.filter(models.Request.requestedBy.like(form.requestor.data))

    return requestlist.all()

或更一般地，您可以执行以下操作：

field_names = ['status', 'assigned', 'requestor']
if form.validate_on_submit():
    requestlist = models.Request.query

    for field in field_names:
        f_value = getattr(form, field).data
        if f_value != 'No Filter':
            requestlist = requestlist.filter(getattr(models.Request, field).like(f_value))

    return requestlist.all()

我看到的唯一问题是表单上的名称和模型有时不匹配。一个例子是requestedBy和requestor。在这种情况下，您可以在field_names中定义字典而不是列表。

更智能的sqlalchemy wtf动态过滤器在烧瓶应用程序中

1 个答案: