Question

id   idtest  result
1      1        2
1      2        1
1      3        2
2      1        2
2      2        1
2      3        1
3      1        1
3      2        2
3      3        1

希望获得具有与条件匹配的相同ID的所有行。例如：获取具有相同id的所有行（idTest = 2和result = 1）和（idTest = 3且result = 2）

结果：

id   idtest  result
1      1        2
1      2        1
1      3        2

查询是什么？谢谢！

Answer 1

你是说这个吗？

SELECT * FROM table WHERE id = 1 and (result = 1 OR result = 2)

他的：

SELECT * 
FROM table WHERE (idTest = 2 OR idTest = 3) AND (result=1 OR result=2)

Answer 2

ID test res

1 1 2

1 2 1

1 3 2

2 1 1

2 2 2

2 3 2

3 1 1

3 2 2

3 3 1

对不起。这将是我的表。并希望获得具有与条件匹配的相同ID的所有行。例如：获取具有相同id的所有行（test = 2和res = 1）和（test = 3且res = 2）

结果：

ID test res

1 1 2

1 2 1

1 3 2

为了获得三行，查询是什么？谢谢！

Answer 3

您似乎希望id的所有行都包含具有该特定组合的行。怎么样：

with ids as (
   select id
   from mytable
   where (idTest=2 and result=1) or (idTest=3 and result=2)
   group by id
   having count(id) = 2
)
select mytable.* from mytable
inner join ids
  on ids.id = mytable.id

这将获取两个条件适用的id列表，然后获取这些id的所有行。

SqlFiddle

Answer 4

您可以使用EXISTS：

SELECT id, idTest, result
FROM dbo.TableName t
WHERE EXISTS
(
   SELECT 1 FROM dbo.TableName t2
   WHERE t.id = t2.id 
     AND(
        ( t2.idTest=2 AND t2.result=1 )
       OR
        ( t2.idTest=3 AND t2.result=2 )
     )
)

Demo

更新：结果不同：

id  idTest  result
1     1     2
1     2     1  <-- satisfies your condition
1     3     2  <-- satisfies your condition
2     1     2
2     2     1  <-- satisfies your condition
2     3     1

因此，我的理解不正确或您的预期结果。我还有ID = 2，因为第二个id-2行符合条件。

Answer 5

SELECT  * 
FROM    table t1
WHERE   EXISTS (SELECT 1 FROM table WHERE id = t1.id AND idtest = 2 AND result = 1)
        AND EXISTS (SELECT 1 FROM table WHERE id = t1.id AND idtest = 3 AND result = 2)

如果您需要更多

，请继续添加更多AND EXISTS

或者如果对你更有意义，你可以使用IN

SELECT  * 
FROM    table
WHERE   id IN (SELECT id from table where idtest = 2 and result = 1)
        AND id IN (SELECT id from table where idtest = 3 and result = 2)

Answer 6

你是否需要一种以通用方式处理条件的方法，比如它们是否在另一个表中的值？或者你只需要一种方法来拉出两个独立条件的结果？

如果是后者，那么这应该有效：

SELECT
  id
FROM
  (SELECT   id 
   FROM tbl 
   WHERE    idTest=2 AND RESULT=1) cond1 INNER JOIN
  (SELECT   id 
   FROM tbl 
   WHERE    idTest=3 AND RESULT=2)  cond2   ON
cond1.id = cond2.id

否则，如果您的条件是通用的并存储在表格中，您需要以下内容：

SELECT
id
FROM
(SELECT id
FROM    tbl FULL OUTER JOIN conditions c
WHERE   c.isUseMe = 1 AND c.SEQ = 1 AND idTest=c.idTestVal AND result=c.resultVal) cond1 INNER JOIN
(SELECT id
FROM    tbl FULL OUTER JOIN conditions c
WHERE   c.isUseMe = 1 AND c.SEQ = 2 AND idTest=c.idTestVal AND result=c.resultVal)  cond2   ON
cond1.id = cond2.id

如果将4个值作为参数传入，则需要类似以下内容：

SELECT
  id
FROM
  (SELECT   id
   FROM tbl 
   WHERE     idTest=@idTestVal1 AND result=@resultVal1) cond1 INNER JOIN
  (SELECT   id
   FROM tbl 
   WHERE     idTest=@idTestVal2 AND result=@resultVal2)  cond2  ON
  cond1.id = cond2.id

选择具有相同ID的数据

6 个答案: