Question

我正在使用TroyGoode MVC PagedList https://github.com/TroyGoode/PagedList 工作得很好，除了我在第一页上有重复的内容

private void makeJsonObjectRequest() {
    ac = new AppController();


    final JsonObjectRequest jsonObjReq = new JsonObjectRequest(Request.Method.GET,
            url, null, new Response.Listener<JSONObject>() {

        @Override
        public void onResponse(JSONObject response) {
            Log.d("test", response.toString());

            try {
                // Parsing json object response
                // response will be a json object


                JSONArray name = response.getJSONArray("data");
                for (int i = 0; i < name.length(); i++) {
                    JSONObject post = (JSONObject) name.getJSONObject(i);

                    try {
                        objectid = post.getString("object_id");

                        newRequest(objectid);

                    }
                    catch (Exception e) {

                   }

                }


            } catch (JSONException e) {
                e.printStackTrace();

            }
        }
    }, new Response.ErrorListener() {

        @Override
        public void onErrorResponse(VolleyError error) {
            VolleyLog.d("test", "Error: " + error.getMessage());
        }
    });

    // Adding request to request queue
    ac.getInstance().addToRequestQueue(jsonObjReq);
}

这给了我HTML输出：

@Html.PagedListPager((IPagedList)ViewData.Model.EnumerableAds, page => Url.Action("MyPage", "Home", new { page }))

我想重新说明：

<div class="pagination-container">
<ul class="pagination">
<li class="PagedList-skipToPrevious"><a href="/home/mypage?page=1" rel="prev">«</a></li>
<li><a href="/home/mypage?page=1">1</a></li>
<li class="active"><a>2</a></li>
<li><a href="/home/mypage?page=3">3</a></li>
<li class="PagedList-skipToNext"><a href="/home/mypage?page=3" rel="next">»</a></li>
</ul>
</div>

通过

<li class="PagedList-skipToPrevious"><a href="/home/mypage?page=1" rel="prev">«</a></li>
<li><a href="/home/mypage?page=1">1</a></li>

有可能吗？

Answer 1

像@ Br4d建议的那样，这是完成此操作的代码

public ActionResult MyPage(int? page=1)
{
     your code here
}

现在您可以为第一页发送空值，它将默认为第1页。

MVC PagedList第一页没有查询字符串

1 个答案: