Question

对于详细程度感到抱歉 - 我尽力将我的代码示例压缩为最小功能类和main()方法。

我正在尝试使用atomic_flag通知我的工作线程中_rx()在调用stop()时退出。

我认为问题在于尝试创建我的工作线程，

thread SanityTestThread(&SanityTest::_rx, *this);

以某种方式与我的atomic_flag

发生冲突

代码示例（不编译）：

 #include <cstdio>
 #include <chrono>

 #include <unistd.h>
 #include <atomic>
 #include <iostream>
 #include <thread>

 using namespace std;

 class SanityTest
 {

   public:
     SanityTest(){}
     void start();
     void stop();

   private:
     void _rx();
     atomic_flag flag;

 }; // end class SanityTest

void SanityTest::_rx()
{
  while(flag.test_and_set())
  {
    this_thread::sleep_for(chrono::seconds(1));
    cout << "'sup foo" << endl;
  }
} // end _rx

void SanityTest::start()
{
  flag.test_and_set();
  thread SanityTestThread(&SanityTest::_rx, *this);
  SanityTestThread.detach();
} // end start

void SanityTest::stop()
{
  flag.clear();
} // end start

int main(){
  SanityTest s;// = SanityTest();
  s.start();
  this_thread::sleep_for(chrono::seconds(10));
  s.stop();
  return 0;
} // end main

为了记录，我可以通过删除对atomic_flag的所有引用并使用for循环替换_rx()循环来编译和运行我的程序，如下所示：

void SanityTest::_rx()
{
  for(int i=0; i <=10; ++ i)
  {
    this_thread::sleep_for(chrono::seconds(1));
    cout << "'sup foo" << endl;
  }
} // end _rx

编译器错误：

In file included from ./SanityTest.cpp:1:0:
./SanityTest.hpp:14:7: note: ‘SanityTest::SanityTest(SanityTest&&)’ is implicitly deleted because the default definition would be ill-formed:
 class SanityTest
       ^
./SanityTest.hpp:14:7: error: use of deleted function ‘std::atomic_flag::atomic_flag(const std::atomic_flag&)’
In file included from /usr/include/c++/4.8/atomic:41:0,
                 from ./SanityTest.hpp:8,
                 from ./SanityTest.cpp:1:
/usr/include/c++/4.8/bits/atomic_base.h:275:5: error: declared here
     atomic_flag(const atomic_flag&) = delete;
     ^
In file included from /usr/include/c++/4.8/functional:55:0,
                 from /usr/include/c++/4.8/thread:39,
                 from ./SanityTest.hpp:10,
                 from ./SanityTest.cpp:1:

...

In file included from ./SanityTest.cpp:1:0:
./SanityTest.hpp:14:7: note: ‘SanityTest::SanityTest(SanityTest&&)’ is implicitly deleted because the default definition would be ill-formed:
 class SanityTest
       ^
./SanityTest.hpp:14:7: error: use of deleted function ‘std::atomic_flag::atomic_flag(const std::atomic_flag&)’
In file included from /usr/include/c++/4.8/atomic:41:0,
                 from ./SanityTest.hpp:8,
                 from ./SanityTest.cpp:1:
/usr/include/c++/4.8/bits/atomic_base.h:275:5: error: declared here
     atomic_flag(const atomic_flag&) = delete;
     ^
In file included from /usr/include/c++/4.8/functional:55:0,
                 from /usr/include/c++/4.8/thread:39,
                 from ./SanityTest.hpp:10,
                 from ./SanityTest.cpp:1:

P.S。这是使用g++ -pthread -std=c++0x -o SanityTest ./SanityTest.cpp

编译的

Answer 1

只需替换

thread SanityTestThread(&SanityTest::_rx, *this);

带

thread SanityTestThread(&SanityTest::_rx, this);

您可能希望传递指向对象的指针而不是对象本身（这将导致复制该对象，并在该副本而不是原始对象上调用成员函数指针&SanityTest::_rx）。

错误消息的原因基本上是std::atomic_flag没有复制构造函数，因此编译器也不会为您的SanityTest类生成默认值，但是再说一遍：你不想在这里复制你的SanityTest对象。

使用std :: atomic_flag和工作线程

1 个答案: