Question

我的表结构：

consumer_id, signup_date, plan_id, subscription_date

它有相同consumer_id的多个subscription_dates。

我希望仅为拥有至少两行数据的用户获取结果对于每个用户，我需要得到一个结果，它给出了由subscription_date ...

排序的前两行

然后我想要拥有至少三行数据的所有用户的另一组结果。对于每个用户，我需要得到一个结果，它给出了前两行和第三行..

依旧......

我感觉它与this类似，但在我的情况下无法让它起作用..

更新

样本表数据：

1 1/1/2015 1 3/1/2015
2 1/1/2015 1 3/1/2015
2 1/1/2015 1 4/1/2015
3 1/1/2015 1 6/1/2015
2 1/1/2015 1 6/1/2015
3 1/1/2015 1 7/1/2015

示例输出1：

2 1/1/2015 1 3/1/2015
2 1/1/2015 1 4/1/2015
3 1/1/2015 1 6/1/2015
3 1/1/2015 1 7/1/2015

示例输出2：

2 1/1/2015 1 4/1/2015
2 1/1/2015 1 6/1/2015

Answer 1

这应该可以让你回答你的第一部分，但是为了得到完整的答案，请告诉我们查询的更多细节（如果我们有一些输出会很好）注意：我假设#test为主表。

select * from 
    (
        SELECT a.consumer_id, a.signup_date, a.plan_id, a.subscription_date
        ,RANK() OVER 
        (PARTITION BY a.consumer_id ORDER BY a.subscription_date ASC) AS Rank1
        FROM #test a
        where a.consumer_id in
            (   
                select consumer_id as count from #test 
                group by consumer_id
                having count(consumer_id)>=2    
            )  
    ) as b
    where b.Rank1<=2


For the second part.


select * from #test

    select * from 
    (
        SELECT a.consumer_id, a.signup_date, a.plan_id, a.subscription_date
        ,RANK() OVER 
        (PARTITION BY a.consumer_id ORDER BY a.subscription_date ASC) AS Rank1
        FROM #test a
        where a.consumer_id in
            (   
                select consumer_id as count from #test 
                group by consumer_id
                having count(consumer_id)>=3    
            )  
    ) as b
    where b.Rank1 between 2 and 3

在第n行后为每个用户获取两行

1 个答案: