Question

if(x>=Window.WIDTH-WIDTH/2)
{ 
    velX=-velX;
    x=Window.WIDTH-WIDTH;
    System.out.println("x: "+x);
    System.out.println("y: "+y);

}
if(x<0 + WIDTH/2||x<0-WIDTH/2){//good works
    x=0+WIDTH/2;
    velX=-velX;
    System.out.println("x: "+x);
    System.out.println("y: "+y);
}
else{
    x+=velX;
}
if(y>=Window.HIEGHT-HIEGHT){
    y=Window.HIEGHT-HIEGHT;
    velY=-velY;
    System.out.println("hit");
    System.out.println("x: "+x);
    System.out.println("y: "+y);
}
if(y<0 + HIEGHT/2){//good math works
    y=0+HIEGHT/2;velY=-velY;
    System.out.println("x: "+x);
    System.out.println("y: "+y);
}
else{y+=velY;}

球应该与jframe的墙碰撞，但是控制最多x和y（ex 800 x 600）的球进入太远而控制开始的那个或x = 0或者y = 0反弹到早期。谁能告诉我为什么？

Answer 1

假设x和y是对象精灵的左上角，而WIDTH和HEIGHT是其尊重尺寸，您可以尝试：

if(x >= Window.WIDTH - WIDTH || x <= 0) {
    velX = -velX;
    System.out.println("hit at: (x,y): " + x + "," + y);
} 
x+=velX;

if(y >= Window.HEIGHT - HEIGHT || y <= 0){
    velY = -velY;
    System.out.println("hit at: (x,y): " + x + "," + y);
}
y+=velY;

让我知道它是否有帮助:)）

球员没有正确地与墙壁碰撞

1 个答案: