Question

Table:    
firstname  |   lastname   |  age      
Joey       |   Sanchez    |  33   
Joey       |   Sanchez    |  33   
Rachel     |   Dudok      |  28

我试图制作一个返回值的MySQL select语句＆＃34; ERROR ＆＃34;在2列重复的年龄列中

我尝试了Case语句但它最终只返回1行。

 SELECT 
 Firstname,
 Lastname,
 CASE
    WHEN count(firstname) AND count(lastname) AND count(age) >= 2 
     THEN '**ERROR**'
     ELSE age
 END
 FROM Table;

Answer 1

您可以尝试group by：

 select Firstname
      , Lastname
      , case when count(*) > 1 then '**ERROR**' else age end
 from Table
 group by  Firstname
         , Lastname
         , age;

或者如果您想要返回包含重复项的所有行：

 select t.Firstname
      , t.Lastname
      , case when (select count(*)
                   from Table
                   where Firstname = t.Firstname and
                         Lastname = t.Lastname and
                         age = t.age) > 1 then '**ERROR**' else age
         end
 from Table t

Answer 2

处理重复记录的方法有很多种。对于大多数情况来说，最好的方法可能是完全使用UNIQUE键来阻止它们：

    ALTER TABLE `mytable` ADD UNIQUE INDEX (`firstname`,`lastname`,`age`);

但是，由于您已经有重复项并且需要找到它们，因此以后就可以了。对于您的特定请求，这是一种处理它的方法：

    SELECT s.`firstname`,s.`lastname`,IF(c.rc > 1,'ERROR',s.`age`) AS 'age'
      FROM `myTable` AS s
      JOIN (SELECT `firstname`, `lastname`, `age`, count(*) AS rc
              FROM `myTable`
             GROUP BY `firstname`,`lastname`,`age`)
        AS c  ON c.`firstname` = s.`firstname`
             AND c.`lastname` = s.`lastname`
             AND c.`age` = s.`age`;

如果您只希望每个名称/年龄组合收到1行，请将DISTINCT添加到外部查询中：

    SELECT DISTINCT s.`firstname`,s.`lastname`,IF(c.rc > 1,'ERROR',s.`age`) AS 'age'
      FROM `myTable` AS s
      JOIN (SELECT `firstname`, `lastname`, `age`, count(*) AS rc
              FROM `myTable`
             GROUP BY `firstname`,`lastname`,`age`)
        AS c  ON c.`firstname` = s.`firstname`
             AND c.`lastname` = s.`lastname`
             AND c.`age` = s.`age`;

根据重复列返回值

2 个答案: