Question

我们有一个4-5-4日历，其中会计年度从2月的星期日开始。对于2016财年，第一天实际上是在1月 - 即1月31日星期日。

我需要编写一个以日期作为输入并返回会计周的函数，例如201552，这将是2015财年的第52个财周。

我认为第一步是确定输入日期的会计年度的开始日期。我知道它总是一个星期天，但我怎么知道它是2月份的第一个星期日，还是1月份的最后一个星期天？

（幸运的是这个功能＆＃39; S目的，我可以忽略偶尔的第53周，我就可以回到第52周时这种情况下，这＆＃39;是因为（我＆＃39; M告知）具有年53财周是不可预测的（无论如何都是在这家公司），并且由人类突发奇想决定。）

有什么建议吗？

更新：

从2005财年到2017财年，我已经为我们公司提供了一份包含FY日历的文件。我看到的模式是：

如果2月1日是星期一，星期二或星期三，那么FY的第一天是1月的最后一个星期日。
如果2月1日是星期四，星期五，星期六或星期日，那么FY的第一天是2月的第一个星期日。

我认为这给了我所需要的东西。

Answer 1

我认为第一步是找到输入日期年份2月1日的星期几。

接下来，找到FY的第一天，这是基于2月1日的一周。如果是星期一，星期二或星期三，那么FY的第一天是1月的最后一个星期日。否则，FY的第一天是1月的第一个星期日。

接下来，确定输入日期是在该FY还是之前的那个。

然后，如果输入日期是前一个FY，请获取该FY的第一天。

接下来，计算从FY第一天到输入日期的天数。除以7，向上舍入到下一个整数。那是FY周。

此时，我将知道输入日期的FY年和FY周，并且可以退货。

更新：

这就是我所拥有的;它适用于我的测试：

Public Function ConvertDateToRawFYWeek(convert_date As Date) As String
'Fiscal year starts on either:
    'the last Sunday in January (if Feb 1st is a Mon, Tue, or Wed), OR:
    'the first Sunday in February (if Feb 1st is Thur, Fri, Sat, or Sun).

    Dim iCalendarYearOfInputDate As Long, iInputMonth As Long, iInputDay As Long, iTmpYear As Long
    Dim iFebFirstOfTmpYear As Long, strFebFirstWeekdayOfTmpYear As String
    Dim iFirstDayofFYOfTmpYear As Long
    Dim iFiscalYearOfInputDate As Long
    Dim iDayOfInputDate As Long
    Dim iDayOfFY As Long, iWeekOfFY As Long, strWeekOfFY As String
    Dim bDone As Boolean

    iCalendarYearOfInputDate = Year(convert_date)
    iInputMonth = Month(convert_date)
    iInputDay = Day(convert_date)
    iDayOfInputDate = CLng(DateValue(convert_date))


    bDone = False 'init.
    iTmpYear = iCalendarYearOfInputDate 'init.
    Do

            '***get the day of the week of feb 1st of tmp date's year:
            iFebFirstOfTmpYear = DateSerial(iTmpYear, 2, 1)
            strFebFirstWeekdayOfTmpYear = Format(iFebFirstOfTmpYear, "DDDD")

            '***get the first day of the FY of the tmp date's year:
            Select Case strFebFirstWeekdayOfTmpYear
                Case "Monday"
                    'first day of the tmp year's FY is the last Sunday of January, which for the tmp year is Jan 31st:
                    iFirstDayofFYOfTmpYear = iFebFirstOfTmpYear - 1
                Case "Tuesday"
                    'first day of the tmp year's FY is the last Sunday of January, which for the tmp year is Jan 30th:
                    iFirstDayofFYOfTmpYear = iFebFirstOfTmpYear - 2
                Case "Wednesday"
                    'first day of the tmp year's FY is the last Sunday of January, which for the tmp year is Jan 29th:
                    iFirstDayofFYOfTmpYear = iFebFirstOfTmpYear - 3
                Case "Thursday"
                    'first day of the tmp year's FY is the first Sunday of February, which for the tmp year is Feb 4th:
                    iFirstDayofFYOfTmpYear = iFebFirstOfTmpYear + 3
                Case "Friday"
                    'first day of the tmp year's FY is the first Sunday of February, which for the tmp year is Feb 3rd:
                    iFirstDayofFYOfTmpYear = iFebFirstOfTmpYear + 2
                Case "Saturday"
                    'first day of the tmp year's FY is the first Sunday of February, which for the tmp year is Feb 2nd:
                    iFirstDayofFYOfTmpYear = iFebFirstOfTmpYear + 1
                Case "Sunday"
                    'first day of the tmp year's FY is the first Sunday of February, which for the tmp year is Feb 1st:
                    iFirstDayofFYOfTmpYear = iFebFirstOfTmpYear
            End Select

            '***get the fiscal year of the input date:
            If iDayOfInputDate >= iFirstDayofFYOfTmpYear Then
                iFiscalYearOfInputDate = iTmpYear
                bDone = True
            Else
                iTmpYear = iTmpYear - 1 'loop again.
            End If

    Loop Until bDone


    '***count the days from that first day of the FY, to the day of the input date.
    'Divide by 7, rounding UP to the next integer. That is the FY week.
    iDayOfFY = iDayOfInputDate - iFirstDayofFYOfTmpYear
    iWeekOfFY = Round((iDayOfFY / 7) + 0.50000000000001) 'round up to next integer.
    strWeekOfFY = Format(iWeekOfFY, "00")

    strFY = Format(iTmpYear, "0000")

    ConvertDateToRawFYWeek = strFY & strWeekOfFY

End Function

给定4-5-4日历和日期，我如何确定该日期的财政周？

1 个答案: