我有3个表（标签，标签，投资组合）
标签有2个字段 - ＆gt; tags_id（ai），tags_name
标签有3个字段 - ＆gt; tag_id（ai），tag_oid（portfolio_id），tag_tid（tags_id）
投资组合有很多领域 - ＆gt; portfolio_id等
我想匹配已标记为＆＃39; PD-02＆＃39;的投资组合记录。我已经能够在三个单独的查询中执行此操作，并且一直尝试将它们组合到一个查询中。标签表包含标签名称/标题，然后标签表格与标签名称建立关系到其他表格 - 如投资组合。
$tags = query_select(
"SELECT *
FROM tags
WHERE tags_name = 'PD-02'");
if (!empty($tags)) {
$related_portfolios = query_select(
"SELECT *
FROM tag
WHERE tag_tid = $tags[0]['tags_id']"
);
if (!empty($related_portfolios)) {
$portfolios = array();
foreach ($related_portfolios as $tkey => $tag) {
$portfolios[] = query_select("SELECT * FROM portfolio WHERE portfolio_id = $tag['tag_oid']");
}
}
}
答案 0 :(得分：2)
您可以尝试<html>
<script language="javascript" type="text/javascript">
<!-- Begin
function convert(input) {
var inputlength = input.length;
input = input.toLowerCase();
var phonenumber = "";
for (i = 0; i < inputlength; i++) {
var character = input.charAt(i);
switch (character) {
case '0':
phonenumber += "0";
break
case 'a':
phonenumber += "1 ";
break;
case 'b':
phonenumber += "2 ";
break;
case 'c':
phonenumber += "3 ";
break;
case 'd':
phonenumber += "4 ";
break;
case 'e':
phonenumber += "5 ";
break;
case 'f':
phonenumber += "6 ";
break;
case 'g':
phonenumber += "7 ";
break;
case 'h':
phonenumber += "8 ";
break;
case 'i':
phonenumber += "9 ";
break;
case 'j':
phonenumber += "10 ";
break;
case 'k':
phonenumber += "11 ";
break;
case 'l':
phonenumber += "12 ";
break;
case 'm':
phonenumber += "13 ";
break;
case 'n':
phonenumber += "14 ";
break;
case 'o':
phonenumber += "15 ";
break;
case 'p':
phonenumber += "16 ";
break;
case 'q':
phonenumber += "17 ";
break;
case 'r':
phonenumber += "18 ";
break;
case 's':
phonenumber += "19 ";
break;
case 't':
phonenumber += "20 ";
break;
case 'u':
phonenumber += "21 ";
break;
case 'v':
phonenumber += "22 ";
break;
case 'w':
phonenumber += "23 ";
break;
case 'x':
phonenumber += "24 ";
break;
case 'y':
phonenumber += "25 ";
break;
case 'z':
phonenumber += "26 ";
break;
case '-':
phonenumber += "-";
break;
case '1':
phonenumber += "a";
break;
case '2':
phonenumber += "b";
break;
case '3':
phonenumber += "c";
break;
case '4':
phonenumber += "d";
break;
case '5':
phonenumber += "e";
break;
case '6':
phonenumber += "f";
break;
case '7':
phonenumber += "g";
break;
case '8':
phonenumber += "h";
break;
case '9':
phonenumber += "i";
break;
case '1-0':
phonenumber += "j";
break;
case '1-1':
phonenumber += "k";
break;
case '1-2':
phonenumber += "l";
break;
case '1-3':
phonenumber += "m";
break;
case '1-4':
phonenumber += "n";
break;
case '1-5':
phonenumber += "o";
break;
case '1-6':
phonenumber += "p";
break;
case '1-7':
phonenumber += "q";
break;
case '1-8':
phonenumber += "r";
break;
case '1-9':
phonenumber += "s";
break;
case '2-0':
phonenumber += "t";
break;
case '2-1':
phonenumber += "u";
break;
case '2-2':
phonenumber += "v";
break;
case '2-3':
phonenumber += "w";
break;
case '2-4':
phonenumber += "x";
break;
case '2-5':
phonenumber += "y";
break;
case '2-6':
phonenumber += "z";
break;
}
}
document.myform.number.value = phonenumber;
return true;
}
// End -->
</script>
<form name=myform>
<table border=0>
<tr>
<td>Alphanumeric #:</td>
<td>
<input type=text size=20 maxlength=20 name=alphabet value="Will123">
</td>
</tr>
<tr>
<td>Converted #:</td>
<td>
<input type="text" size=20 maxlength=20 name="number">
</td>
</tr>
<tr>
<td align=center colspan=2>
<input type=button value="Convert" onClick="return convert(document.myform.alphabet.value)">
</td>
</table>
</form>
</html>
：
inner join答案 1 :(得分：0)
此查询可能有效。
SELECT *
FROM tags, tag, portfolio
WHERE tags.tag_name='PD-02'
AND tags.tag_id=tags.tags_id
AND tags.tag_oid=portfolio.portfolio_id;