Question

我认为今天的咖啡不够浓郁。我需要查询表fb-celebotd以获得与fb-celebotd.celebdate匹配的photoid。所需的大多数其他信息都取决于照片表。

以下是给我一个mysql错误：

Select photos.*,photographer.name, events.eventname, events.eventhome, subevents.subeventname, photodir.photodir, fb-celebotd.celebdate, fb-celebotd.trivia 
      from photos 
LEFT JOIN fb-celebotd ON (photos.photoid = fb-celebotd.photoid) 
LEFT JOIN photodir ON (photos.photodirid = photodir.photodirid) 
LEFT JOIN photographer ON (photos.photographerid = photographer.photographerid) 
LEFT JOIN events ON (photos.eventid = events.eventid) 
LEFT JOIN subevents ON (photos.subeventid = subevents.subeventid) 
WHERE fb-celebotd.celebdate=1277092800

这在一个查询中是可行的，还是我必须首先查询fb-celebotd的photoid和琐事，然后根据photoid查询其他表？

感谢。

Answer 1

fb-celebotd（带破折号）是fb_celebotd（带下划线）吗？如果表名有破折号，那么您必须引用表名："fb-celebotd"。否则，短划线将被视为减号，并尝试从fb中减去celebotd（均为未知）。

Answer 2

如果你真的有一个名为fb-celebotd的表，那么每次在查询中使用它时都需要引用表名：

Select photos.*,photographer.name, events.eventname, events.eventhome, subevents.subeventname, photodir.photodir, `fb-celebotd`.celebdate, `fb-celebotd`.trivia 
      from photos 
LEFT JOIN `fb-celebotd` ON (photos.photoid = `fb-celebotd`.photoid) 
LEFT JOIN photodir ON (photos.photodirid = photodir.photodirid) 
LEFT JOIN photographer ON (photos.photographerid = photographer.photographerid) 
LEFT JOIN events ON (photos.eventid = events.eventid) 
LEFT JOIN subevents ON (photos.subeventid = subevents.subeventid) 
WHERE `fb-celebotd`.celebdate=1277092800

左连接错误？

2 个答案: