Question

我有以下xml

  <Amendment.Text>
    <Page>4</Page>
    <Line>4</Line>
    <Bold>It is a </Bold>   
    <Italic>Beautiful Day</Italic>
    <Bold>In London</Bold>
    <Italic>17 June 2015</Italic>   
</Amendment.Text>

我希望将<Bold>和<Italic>元素值反序列化为单个值字符串数组属性

我的可序列化类如下所示，它不起作用。

[Serializable]
    public class AmdTextType
    {

        public string Page { get; set; }

        public string Line { get; set; }


        public string[] Content { get; set; }


    }

Answer 1

为什么不从原始元素计算它：

[XmlElementAttribute("Italic", typeof(string))]        
public string Italic { get; set; }

[XmlElementAttribute("Bold", typeof(string))]
public string Bold { get; set; }

public string[] Content { 
    get {
        return new string[] { this.Italic, this.Bold };
    }
}

Answer 2

这是另一种方法。我通过使用编辑 - ＆gt;获得了大部分内容。选择性粘贴 - ＆gt;在Visual Studio中粘贴XML作为类。这还包括一系列名称，以防您需要返回粗体或斜体

[XmlType(AnonymousType = true)]
[XmlRoot("Amendment.Text", Namespace = "", IsNullable = false)]
public partial class AmendmentText
{
    [XmlElement("Line", typeof(int))]
    public int Line { get; set; }

    [XmlElement("Page", typeof(int))]
    public int Page { get; set; }

    [XmlElement("Bold", typeof(string))]        
    [XmlElement("Italic", typeof(string))]        
    [XmlChoiceIdentifier("ContentName")]
    public object[] Content { get; set; }

    [XmlElement("ContentName")]
    [XmlIgnore()]
    public ContentName[] ContentName { get; set; }

}

[XmlType(IncludeInSchema = false)]
public enum ContentName
{        
    Bold,
    Italic,        
}

将多个xml元素反序列化为单个对象属性

2 个答案: