OutofMemory Android BitMap

Question

我需要将手机中的所有图像上传到服务器，但问题是我使用Async来记忆内存。

我看到很多解决方案，他们要求用户缩小图像，但我需要发送原始图像而不进行压缩或修改。

我尝试了Thread.sleep（5000）;

我也尝试过以下操作，但问题是它在上传之前清理了我的Bitmap，因为它的异步

bm.recycle（）; bm = null;

无论如何我可以上传图片ONE BY ONE

     @Override
        protected void onCreate(Bundle savedInstanceState) {


    picturePath = Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DCIM).getAbsolutePath()+"/Camera/";
            Log.d("Files", "Path: " + picturePath);
            File f = new File(picturePath);
            File file[] = f.listFiles();
            Log.d("Files", "Size: " + file.length);
            for (int i=0; i < file.length; i++)
            {
                Log.d("Files", "FileName:" + file[i].getName());

                // Image location URL
                Log.e("Files", "----------------" + picturePath+file[i].getName());



         // Image
                    Bitmap bm = BitmapFactory.decodeFile(picturePath + file[i].getName());
                    ByteArrayOutputStream bao = new ByteArrayOutputStream();
bm.compress(Bitmap.CompressFormat.JPEG, 75, bao);
                    byte[] ba = bao.toByteArray();
                    ba1 = Base64.encodeToString(ba, Base64.DEFAULT);

                    Log.d("Files", "Uploading");

                    new uploadToServer().execute();

                }

                super.onCreate(savedInstanceState);
                setContentView(R.layout.activity_main);
            }



     public class uploadToServer extends AsyncTask<Void, Void, String> {


            protected void onPreExecute() {
                super.onPreExecute();
            }

            @Override
            protected String doInBackground(Void... params) {

                ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
                nameValuePairs.add(new BasicNameValuePair("base64", ba1));
                nameValuePairs.add(new BasicNameValuePair("ImageName", System.currentTimeMillis() + ".jpg"));
                try {
                    HttpClient httpclient = new DefaultHttpClient();
                    HttpPost httppost = new HttpPost(URL);
                    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
                    HttpResponse response = httpclient.execute(httppost);
                    String st = EntityUtils.toString(response.getEntity());
                    Log.v("Files", "In the try Loop" + st);

                } catch (Exception e) {
                    Log.v("Files", "Error in http connection " + e.toString());
                }
                return "Success";

            }

            protected void onPostExecute(String result) {
                super.onPostExecute(result);

            }
        }

Answer 1

您需要使用HttpUrlConnection的.setChunkedStreamingMode(1024);

以块的形式发送数据

请参阅此answer以获取示例