Question

我坚持检索下面的json响应是json输出。非常感谢您的帮助。

{ "productHeader" : { "totalHits" : 684 }, "products" : [ { "name" : "Victoria Hotels", "productImage" : { "url" : "http://hotels.com/hotels/9000000/8640000/8633700/8633672/8633672_20_b.jpg" }, "language" : "en", "description" : "Location. Victoria Hotels is in Foshan (Nanhai) and area attractions include Renshou Temple and New Plaza Stadium. Additional regional attractions include Guangdong Folk Art Museum and Bright Filial Piety Temple.", "identifiers" : { }, "fields" : [ { "name" : "regions2", "value" : "Guangdong" },

请帮我提取特定值。例如，如果我需要获取名称，请从json响应中获取图像URL。

Answer 1

您可以使用json_decode将JSON字符串解析为数组并访问它的值：

// assuming, that $string contains the json response
// second parameter to true, to get an array instead of an object
$data = json_decode( $string, true );
if ( $data ) {
  echo $data['products'][0]['name'];
  // or whatever value
} else {
  echo 'JSON could not be parsed, error: ' . json_last_error();
}

要显示products数组中的所有值，请简单循环：

if ( $data ) {
  foreach($data['products'] as $product){
      echo $product['name'];
  }
  // or whatever value
} else {...

Answer 2

如果您要使用PHP获取值，请查看：

$decodedJson = json_decode($json, true);
print_r($decodedJson);

您将获得一个数组，以获取在循环中执行此操作所需的图像源和其他标记，或选择具体的索引，如：

echo $decodedJson['productHeader']['products'][0]['productImage']['url'];

在JS中，您应该以相同的方式提取值。

json响应处理问题

2 个答案: