Question

我有这些表格：

CREATE TABLE PRODUCT (
  ID NUMBER(19,0) NOT NULL,
  CONSTRAINT PRODUCT_PK
  PRIMARY KEY (ID)
  USING INDEX (
    CREATE UNIQUE INDEX PRODUCT_PK
    ON PRODUCT(ID)
    ...
  )
)
...

CREATE TABLE PRODUCT_LOCALE (
  PRODUCT_ID NUMBER(19,0) NOT NULL,
  LOCALE VARCHAR2(12 CHAR) NOT NULL,
  NAME VARCHAR2(160 CHAR),
  CONSTRAINT PRODUCT_LOCALE_PK
  PRIMARY KEY (PRODUCT_ID,LOCALE)
)
...

由本课程代表：

public class Product extends LocalizedEntity<Product.LocalizedFields> {

  ....

  private Long id;

  public Long getId() {
    return id;
  }

  public void setId(Long id) {
    this.id = id;
  }

  public static class LocalizedFields implements Serializable {

    private String name;

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }
  }

}

及其超级

public abstract class LocalizedEntity<T> implements serializable {

  ....

  private Map<Locale, T> localizedFields = new HashMap<Locale, LF>();

  public Map<Locale, T> getLocalizedFields() {
    return localizedFields;
  }

  public void setLocalizedFields(Map<Locale, T> localizedFields) {
    this.localizedFields = localizedFields;
  }
}

我正在使用Hibernate和.hbm.xml文件，这个标签正在运行：

.....
<map name="localizedFields" table="product_locale" lazy="false" fetch="select" batch-size="100">
  <cache usage="read-write" />
  <key column="product_id" not-null="true" />
  <map-key type="locale">
    <column name="locale" length="12" not-null="true" />
  </map-key>
  <composite-element class="com.myproject.Product$LocalizedFields">
    <property name="name" type="string">
        <column name="name" length="500" />
    </property>
  </composite-element>
  </map>
.....

现在我必须使用Annotations，所以我已经迁移到了这个：

@Entity
@Table(name = "product")
public class Product extends LocalizedEntity<Product.LocalizedFields> {

  ....

  private Long id;

  @Id
  @Column(name = "id")
  @GeneratedValue(strategy= GenerationType.AUTO)
  public Long getId() {
    return id;
  }

  public void setId(Long id) {
    this.id = id;
  }

  @ElementCollection(fetch = FetchType.EAGER)
  @JoinTable(name = "product_locale", joinColumns = @JoinColumn(name = "product_id", nullable = false))
  @MapKeyClass(value = Locale.class)
  @MapKeyColumn(name = "locale", length = 12, nullable = false)
  @BatchSize(size = 100)
  @Fetch(FetchMode.SELECT)
  @Cache(usage = CacheConcurrencyStrategy.READ_WRITE)
  @Embedded
  public Map<Locale, LocalizedFields> getLocalizedFields() {
    return super.getLocalizedFields();
  }

  @Embeddable
  public static class LocalizedFields implements Serializable {

    ....

    private String name;

    @Column(name = "name", length = 500, nullable = false)
    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }
  }
}

而且......

@MappedSuperclass
public abstract class LocalizedEntity<T> implements serializable {

  ....

  private Map<Locale, T> localizedFields = new HashMap<Locale, LF>();

  public Map<Locale, T> getLocalizedFields() {
    return localizedFields;
  }

  public void setLocalizedFields(Map<Locale, T> localizedFields) {
    this.localizedFields = localizedFields;
  }
}

它抛出了这个错误：

引起：org.hibernate.MappingException：无法确定：java.util.Map的类型，在表：product，对于列：[org.hibernate.mapping.Column（localizedFields）] 在org.hibernate.mapping.SimpleValue.getType（SimpleValue.java:349）在org.hibernate.mapping.SimpleValue.isValid（SimpleValue.java:322）在org.hibernate.mapping.Property.isValid（Property.java:241）在org.hibernate.mapping.PersistentClass.validate（PersistentClass.java:496）在org.hibernate.mapping.RootClass.validate（RootClass.java:270）在org.hibernate.cfg.Configuration.validate（Configuration.java:1360）在org.hibernate.cfg.Configuration.buildSessionFactory（Configuration.java:1851）在org.hibernate.cfg.Configuration.buildSessionFactory（Configuration.java:1930）在org.springframework.orm.hibernate4.LocalSessionFactoryBuilder.buildSessionFactory（LocalSessionFactoryBuilder.java:372）在org.springframework.orm.hibernate4.LocalSessionFactoryBean.buildSessionFactory（LocalSessionFactoryBean.java:454）在org.springframework.orm.hibernate4.LocalSessionFactoryBean.afterPropertiesSet（LocalSessionFactoryBean.java:439）在org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods（AbstractAutowireCapableBeanFactory.java:1633）在org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean（AbstractAutowireCapableBeanFactory.java:1570） ... 103更多

如果我用@MapKey替换@MapKeyClass（value = Locale.class）和@MapKeyColumn（＆＃34; locale＆＃34;）会抛出此错误：

引起：org.hibernate.AnnotationException：找不到关联的类：com.myproject.Product $ LocalizedFields at org.hibernate.cfg.annotations.MapBinder.bindKeyFromAssociationTable（MapBinder.java:133） at org.hibernate.cfg.annotations.MapBinder.access $ 000（MapBinder.java:76）在org.hibernate.cfg.annotations.MapBinder $ 1.secondPass（MapBinder.java:111）在org.hibernate.cfg.CollectionSecondPass.doSecondPass（CollectionSecondPass.java:70）在org.hibernate.cfg.Configuration.originalSecondPassCompile（Configuration.java:1697）在org.hibernate.cfg.Configuration.secondPassCompile（Configuration.java:1426）在org.hibernate.cfg.Configuration.buildSessionFactory（Configuration.java:1846）在org.hibernate.cfg.Configuration.buildSessionFactory（Configuration.java:1930）在org.springframework.orm.hibernate4.LocalSessionFactoryBuilder.buildSessionFactory（LocalSessionFactoryBuilder.java:372）在org.springframework.orm.hibernate4.LocalSessionFactoryBean.buildSessionFactory（LocalSessionFactoryBean.java:454）在org.springframework.orm.hibernate4.LocalSessionFactoryBean.afterPropertiesSet（LocalSessionFactoryBean.java:439）在org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods（AbstractAutowireCapableBeanFactory.java:1633）在org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean（AbstractAutowireCapableBeanFactory.java:1570） ... 103更多

Answer 1

我发现问题是关键＆＃34; Locale＆＃34;

根据JPA文档（http://docs.oracle.com/javaee/6/api/index.html?javax/persistence/MapKeyClass.html）：

＆＃34;指定类型关联的映射键的类型 java.util.Map。 map键可以是基本类型，可嵌入类，或实体＆＃34;

Locale不是基本类型，可嵌入或实体，它是Hibernate使用其内部类型＆＃34; locale＆＃34;管理的自定义类型。（它是org.hibernate.type.LocaleType的别名），因此JPA没有注释来管理它。

要解决它，我们必须使用Hibernate添加的注释@MapKeyType来映射UserTypes或Hibernate的自定义类型，而不是注释JPA（https://hibernate.atlassian.net/browse/HHH-5507）。

通过这些注释，它必须起作用：

@ElementCollection(fetch = FetchType.EAGER)
@JoinTable(name = "product_locale", joinColumns = @JoinColumn(name = "product_id", nullable = false))
@MapKeyColumn(name = "locale", length = 12, nullable = false)
@MapKeyType(value = @Type(type = "locale"))
@BatchSize(size = 100)
@Fetch(FetchMode.SELECT)
@Cache(usage = CacheConcurrencyStrategy.READ_WRITE)

Answer 2

注释 @MappedSuperclass 文档：

指定一个其映射信息应用于的类从中继承的实体。映射的超类没有单独的为它定义的表。

当hibernate构建映射时，它为每个类创建一个 org.hibernate.mapping.PersistentClass ，并且对于每个属性一个'value'，根据注释（org。）有不同类型的值。 hibernate.mapping.ManyToMany，org.hibernate.mapping.OneToMany，org.hibernate.mapping.SimpleValue等）。注释 @ElementCollection 必须声明为 org.hibernate.mapping.Component 但如果您看到堆栈跟踪错误来自SimpleValue：

引起：org.hibernate.MappingException：无法确定：java.util.Map的类型，在表：product，对于列：[org.hibernate.mapping.Column（localizedFields）]在 org。 hibernate.mapping.SimpleValue .getType（SimpleValue.java:349）at ....

Hibernate忽略了在子元素上声明的注释，简单的解决方案是删除注释 @MappedSuperclass 。

另一个解决方案是告诉孩子们hibernate该字段已被覆盖，但我尝试使用 @AssociationOverride 或 @AttributeOverride 但没有成功。< / p>

以区域设置为键的地图的Hibernate注释

2 个答案: