Question

我有两个问题。两者都返回

 select sum (Amount) as 'Less then 30 days', [Fluids Management$Cust_ Ledger    Entry].[Customer No_]
FROM [Fluids Management$Detailed Cust_ Ledg_ Entry]
group by [Fluids Management$Cust_ Ledger Entry].[Customer No_]


 select sum ([Debit Amount]) as 'Less then 30 days', [Fluids Management$Cust_ Ledger Entry].[Customer No_]
 FROM [Fluids Management$Detailed Cust_ Ledg_ Entry]
  group by [Fluids Management$Cust_ Ledger Entry].[Customer No_]

都有更多的深入标准，我只是没有包含它。无论如何，我想采取第一个查询，并检查第二个查询中是否存在客户。如果是这样，请将金额总和加到借方金额中。如果id没有显示在第二个查询中，则只返回第一个查询中的总和。它全部归客户所有。请帮忙

Answer 1

eaiset方式可能是内联UNION查询的SUM

SELECT SUM (AMOUNT), [Customer No_]
FROM 

(
 select Amount 
          [Fluids Management$Cust_ Ledger    Entry].[Customer No_]
FROM 
        [Fluids Management$Detailed Cust_ Ledg_ Entry]
UNION ALL 
select [Debit Amount] as 'Less then 30 days', 
         [Fluids Management$Cust_ Ledger Entry].[Customer No_]
 FROM [Fluids Management$Detailed Cust_ Ledg_ Entry]
) 

GROUP BY  [Customer No_]

您没有指定数据库，因此您可能需要为内联视图设置别名才能使其正常工作

Answer 2

将两个查询放在派生表中并LEFT JOIN：

SELECT a.[Customer No_], a.'Less then 30 days' + COALESCE(b.'Less then 30 days', 0)
FROM
 (
   SELECT SUM (Amount) AS 'Less then 30 days', [Fluids Management$Cust_ Ledger Entry].[Customer No_]
   FROM [Fluids Management$Detailed Cust_ Ledg_ Entry]
   GROUP BY [Fluids Management$Cust_ Ledger Entry].[Customer No_]
 ) AS a
LEFT JOIN
 (
   SELECT SUM ([Debit Amount]) AS 'Less then 30 days', [Fluids Management$Cust_ Ledger Entry].[Customer No_]
   FROM [Fluids Management$Detailed Cust_ Ledg_ Entry]
   GROUP BY [Fluids Management$Cust_ Ledger Entry].[Customer No_]
 ) AS b
ON a.[Customer No_] = b.[Customer No_]

但是当您访问同一个表两次时，您可以使用SUM（CASE）将其更改为单个查询

sql结合两个子查询并总计总和

2 个答案: