Question

对于模棱两可的标题感到抱歉，但我不知道如何更好地解释。无论如何，我创建了一个代码来解析c＃中的Json，这个结构：

{
 "_links": {
   "self": { "href": "http://api.football-data.org/alpha/soccerseasons/354" },
   "teams": { "href": "http://api.football-data.org/alpha/soccerseasons/teams"      },
   "fixtures": { "href": "http://api.football-data.org/alpha/soccerseasons/fixtures" },
   "leagueTable": { "href": "http://api.football-data.org/alpha/soccerseasons/leagueTable" }
},
"caption": "Premier League 2014/15",
"league": "PL",
"year": "2014",
"numberOfTeams": 20,
"numberOfGames": 380,
"lastUpdated": "2014-12-21T10:47:43Z"
}

在我的代码中，我可以获得"self"，"teams"，"fixtures"和"leagueTable"的值。但是如何在Json的结构中看到这个参数有一个关联的链接。我想获取此链接，因为我需要下一次解析数据。

如何获得这个？

实际上，这是我的代码：

    private void button_Click(object sender, RoutedEventArgs e)
    {
        string requestUrl = "http://api.football-data.org/alpha/soccerseasons";
        HttpWebRequest request = WebRequest.Create(requestUrl) as HttpWebRequest;
        request.Method = "GET";
        request.ContentType = "application/json";

        string responseText;
        using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)
        using (var responseStream = new StreamReader(response.GetResponseStream()))
        {
            responseText = responseStream.ReadToEnd();
        }

        List<RootObject> obj = JsonConvert.DeserializeObject<List<RootObject>>(responseText);
        LinksClass link = JsonConvert.DeserializeObject<LinksClass>(obj._links);
        //89a6ba3f0a6f455b9313107d977f4a43
        foreach (var item in obj)
        {
            Console.WriteLine(
                              item.Year + " " +
                              item.League + " " +
                              item.Caption + " " +
                              item.NumberOfGames + " " +
                              item.NumberOfTeams + " " +
                              item.LastUpdated);
        }
    }


    public class Self
    {
        public string href { get; set; }
    }

    public class Teams
    {
        public string href { get; set; }
    }

    public class Fixtures
    {
        public string href { get; set; }
    }

    public class LeagueTable
    {
        public string href { get; set; }
    }

    public class Links
    {
        [JsonProperty("self")]
        public Self Self { get; set; }
        [JsonProperty("teams")]
        public Teams Teams { get; set; }
        [JsonProperty("fixtures")]
        public Fixtures Fixtures { get; set; }
        [JsonProperty("leagueTable")]
        public LeagueTable LeagueTable { get; set; }
        public string data { get; set; }
    }

    public class RootObject
    {
        [JsonProperty("_links")]
        public Links Links { get; set; }
        [JsonProperty("caption")]
        public string Caption { get; set; }
        [JsonProperty("League")]
        public string League { get; set; }
        [JsonProperty("Year")]
        public string Year { get; set; }
        [JsonProperty("numberOfTeams")]
        public int NumberOfTeams { get; set; }
        [JsonProperty("NumberOfGames")]
        public int NumberOfGames { get; set; }
        [JsonProperty("LastUpdated")]
        public string LastUpdated { get; set; }
    }

    public class LinksClass
    {
        [JsonProperty("self")]
        public Self Self { get; set; }
        [JsonProperty("teams")]
        public Teams Teams { get; set; }
        [JsonProperty("fixtures")]
        public Fixtures Fixtures { get; set; }
        [JsonProperty("leagueTable")]
        public LeagueTable LeagueTable { get; set; }
    }
}

你怎么看我创造了这个：

LinksClass link = JsonConvert.DeserializeObject<LinksClass>(obj._links);

和获取此链接的适当类，但我无法得到链接，这种方式我认为是错误的。

Answer 1

实际上你应该已经拥有第一个反序列化的所有链接值，不需要第二次调用DeserializeObject：

List<RootObject> obj = JsonConvert.DeserializeObject<List<RootObject>>(responseText);

foreach (var item in obj)
{
    //This is how you access the links:
    Console.WriteLine(item.Links.Self.href + " ");
}

如何获取JSON的子参数

1 个答案: