Question

鉴于此数组：

["/Item A/", "/Item B/"]

和一行：

Here's a line of text that includes /Item B/

检查该行是否至少包含一个来自数组的短语，这是一种好的，惯用的Ruby方法吗？

Answer 1

几种方式。速度可能取决于阵列和线的大小。可能想要运行一些基准来看：

> a = ["/Item A/", "/Item B/"]
> l = "Here's a line of text that includes /Item B/"

然后使用any?：

> a.any?{|e| l.index(e)}
=> true

或使用Regexp：

> l =~ Regexp.union(a)
=> 36

Answer 2

以上回答非常好，您还可以使用any?和include?

尝试以下代码段

a = ["/Item A/", "/Item B/"]
l = "Here's a line of text that includes /Item B/"

a.any? { |e| l.include?(e) }
=> true

Answer 3

如果数组的元素遵循模式，如您的示例所示，您可能希望使用正则表达式来提高效率。例如：

a = ("A".."X").map { |c| "/Item #{c}/" }
  #=> ["/Item A/", "/Item B/", "/Item C/",..., "/Item X/"] 

"I considered /Item Y/ and /Item R/. I want the R!" =~ /\/Item [A-X]\// #=> 26 
"I considered /Item Y/ and /Item Z/. I want the Z!" =~ /\/Item [A-X]\// #=> nil

Ruby - 数组中的至少一个项目也在行

3 个答案: