尝试比较来自两个数据集的多组数据。蟒

Question

我正在尝试比较来自两个不同数据集的多组数据。我使用csv.DictReader引用了每个csv。然后我创建了一个函数处理程序来处理每个函数。每个函数处理一组不同的数据，正在使用的两个数据集被分解为一组函数。

以下是导致错误的函数，并且没有keyerror，因为它引用的列名没有问题。然后每个函数由secMastHandler（）函数处理，我将每个函数引用为 inputData = secMastHandler（）。我可以将每个函数的数据作为列表inputData [n]引用，它可以正常压缩zip（inputData [a]，inputData [b]）并执行条件（如果行[0] == line [1] :) 。

但是zip（）和后续if语句中的两个以上元素不起作用并获取有关键错误的错误消息。在这个例子中，这似乎是一个奇怪的错误。所以真正的问题是如何在同一个if语句中比较这些多个数据集？

def frfSecDict(): ## function handling the frfpost data 
                  ## from the section file data set
    import csv
    reader = csv.DictReader(outData)
    for row in reader:
        frfpost = str(row['FRFPOST']) ## Line 61. There is not keyError here
        frfpostFlt = round(float(frfpost),3)
        yield frfpostFlt

line 61, in frfSecDict
    frfpost = str(row['FRFPOST'])
KeyError: 'FRFPOST'


def secMastHandler(): ## handler function for functions handling data from
                  ## multiple data sources
    gen0 = corrSecDict()
    gen1 = svySecDict() ## this is inputData[1]
    gen2 = frfSecDict() ## this is inputData[2]
    gen3 = trfSecDict()
    gen4 = corrMastDict()
    gen5 = svyMastDict() ## this is inputData[5]
    gen6 = frfMastDict() ## this is inputData[6]
    gen7 = trfMastDict()
    return gen0,gen1,gen2,gen3,\
        gen4,gen5,gen6,gen7

def SecMastPrinter(): ## this function should yield output from multiple
                  ## datasets based upon the conditions from
                  ## the zipped inputData datasets.
    inputData = secMastHandler()
    for line in zip(inputData[1],inputData[5],\
                inputData[2],inputData[6]): ## doesnt seem to like this
                                            ## second line in the zip
        if line[0] == line[1] and line[2] == line[3]: ## this not possible?
            output = line[:]
            yield output

def frfSecMastPrinter():
    inputData = secMastHandler()
    for line in zip(inputData[2],inputData[6]): ## but just a one line
                                                ## zip works just fine
        if line[0] == line[1]:
            output = line[:]
            yield output