Question

我在laravel 5中遇到了这个错误。

这是我面临错误的控制器功能（在我所做的行（$vendor->client[0]->id）中：

public function show($username) {
Log::info('Vendors Controller : show function with '.$username);
$vendor = VendorProfile::where('username', $username)->first();
$output = print_r($vendor,1);
Log::info($output);
if($vendor) {
  Log::info('client '. $vendor->client);
  $client = Client::find($vendor->client[0]->id);
  $title = $client->profile->company_name;

$output打印为：

VendorProfile和Client模型连接为：

VendorProfile模型中的

：

    protected $morphClass = 'MorphVendorProfile';

  // Defining 'Polymorphic' Relationship with Client Model
  public function client() {
    return $this->morphMany('App\models\Client', 'profile');
  }

我的config/app.php中有别名：

'MorphVendorProfile'=> 'App\models\VendorProfile'

在客户端模型中：

public function profile() {
        return $this->morphTo();
    }

更新

将代码从laravel 4.2迁移到laravel 5时发生此错误。所以现在，当我运行基于4.2版本和SAME数据库的先前代码时，它并没有给我任何错误，所以我认为问题在于代码，而不是数据库。我确信＆＃39;变形＆＃39;存在问题。关系，我必须在迁移过程中稍微修改一下，使其在其他页面上工作。

这是我的Eloquent / Model.php中的morphTo函数：

/**
 * Define a polymorphic, inverse one-to-one or many relationship.
 *
 * @param  string  $name
 * @param  string  $type
 * @param  string  $id
 * @return \Illuminate\Database\Eloquent\Relations\MorphTo
 */
public function morphTo($name = null, $type = null, $id = null)
{
    // If no name is provided, we will use the backtrace to get the function name
    // since that is most likely the name of the polymorphic interface. We can
    // use that to get both the class and foreign key that will be utilized.
    if (is_null($name))
    {
        list(, $caller) = debug_backtrace(false, 2);

        $name = snake_case($caller['function']);
    }

    list($type, $id) = $this->getMorphs($name, $type, $id);

    // If the type value is null it is probably safe to assume we're eager loading
    // the relationship. When that is the case we will pass in a dummy query as
    // there are multiple types in the morph and we can't use single queries.
    if (is_null($class = $this->$type))
    {
        Log::info('eagerly loading');
        return new MorphTo(
            $this->newQuery(), $this, $id, null, $type, $name
        );
    }

    // If we are not eager loading the relationship we will essentially treat this
    // as a belongs-to style relationship since morph-to extends that class and
    // we will pass in the appropriate values so that it behaves as expected.
    else
    {
        Log::info('not eagerly loading');
        Log::info($class);
        $instance = \App::make('\App\models\\'.$class);
        $output = print_r($instance,1);
        Log::info('*'.$output.'*');
        return new MorphTo(
            $instance->newQuery(), $this, $id, $instance->getKeyName(), $type, $name
        );
    }
}

Answer 1

检查您的命名空间。确保您设置的多态关系引用供应商和客户端模型中的完整命名空间

Laravel ErrorException未定义的偏移量：0

更新

1 个答案: