Question

目标：要解析以下 json 字符串并分别获取提及的值，稍后将这些分隔值插入 mysql 数据库。
我在JsonLint

上检查了我的json字符串

USER_NAME，
selected_date，
selected_project，

tasks，4.1.task_name，4.2 work_hours

{
"user_name": "USER",
"selected_date": "2015-06-08",
"selected_project": "Project1",
"tasks": [
    {
        "task_name": "task-1",
        "work_hours": [
            {
            "Monday": " 3"
            },
            {
            "Tuesday": " 0"
            },
            {
            "Wednesday": " 2.5"
            },
            {
            "Thursday": " 2"
            },
            {
            "Friday": " 0"
            },
            {
            "Saturday": " 0"
            },
            {
            "Sunday": " 0"
            }
        ]
    }
] 
}

PHP代码是：

$str_json = file_get_contents('php://input'); //($_POST doesn't work here)
$response = json_decode($str_json, true); // decoding received JSON to array
$jsonIterator = new RecursiveIteratorIterator(
new RecursiveArrayIterator(json_decode($response, TRUE)),
RecursiveIteratorIterator::SELF_FIRST);
foreach ($jsonIterator as $key => $val) 
{
 if(is_array($val)) 
 {
   echo "$key:\n";
 } 
 else 
 {
   echo "$key => $val\n";
   echo "$value";
 }
}

由于我是JSON和PHP的新手，我无法解决这个问题，我们将不胜感激。

Answer 1

    <?
$json = '{
"user_name": "USER",
"selected_date": "2015-06-08",
"selected_project": "Project1",
"tasks": [
    {
        "task_name": "task-1",
        "work_hours": [
            {
            "Monday": " 3"
            },
            {
            "Tuesday": " 0"
            },
            {
            "Wednesday": " 2.5"
            },
            {
            "Thursday": " 2"
            },
            {
            "Friday": " 0"
            },
            {
            "Saturday": " 0"
            },
            {
            "Sunday": " 0"
            }
        ]
    }
] 
}';

// decode your json  into associative arrays
$decoded = json_decode($json, true);

// use array
echo "Username: ". $decoded['user_name'] . "<br>";
echo "Date: ". $decoded['selected_date'] . "<br>";
echo "project: ". $decoded['selected_project'] . "<br>";
echo "Task: ". $decoded['tasks'][0]['task_name'] . "<br>";

foreach($decoded['tasks'][0]['work_hours'] as $key => $value) {
    foreach($value as $key2 => $value2){
        echo $key2 . ": ". $value2 . "<br>";
    }
}
?>

在PHP上解析JSON并提取特定值

1 个答案: