Question

我正在开发基于XMPP的项目。我可以发送消息并在会话屏幕中显示，但是当我收到消息时，它只显示在alertview中，无法在会话屏幕中看到。

 - (void)xmppStream:(XMPPStream *)sender didReceiveMessage:(XMPPMessage *)message
{

DDLogVerbose(@"%@: %@", THIS_FILE, THIS_METHOD);


if ([message isChatMessageWithBody])
{
    XMPPMessageArchivingCoreDataStorage *xmppMessageStorage = [XMPPMessageArchivingCoreDataStorage sharedInstance];
    XMPPMessageArchiving *xmppMessageArchiving = [[XMPPMessageArchiving alloc] initWithMessageArchivingStorage:xmppMessageStorage];

    [xmppMessageArchiving activate:xmppStream];
    [xmppMessageArchiving addDelegate:self delegateQueue:dispatch_get_main_queue()];
    XMPPUserCoreDataStorageObject *user = [xmppRosterStorage userForJID:[message from]
                                                             xmppStream:xmppStream
                                                   managedObjectContext:[self managedObjectContext_roster]];

    [[NSNotificationCenter defaultCenter] postNotificationName:MessageRecivedNotif object:message];

    NSString *body = [[message elementForName:@"body"] stringValue];
    NSString *displayName = [user displayName];

    if ([[UIApplication sharedApplication] applicationState] == UIApplicationStateActive)
    {
        UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:displayName
                                                            message:body
                                                           delegate:nil
                                                  cancelButtonTitle:@"Ok"
                                                  otherButtonTitles:nil];
        [alertView show];
    }
    else
    {
        // We are not active, so use a local notification instead
        UILocalNotification *localNotification = [[UILocalNotification alloc] init];
        localNotification.alertAction = @"Ok";
        localNotification.alertBody = [NSString stringWithFormat:@"From: %@\n\n%@",displayName,body];

        [[UIApplication sharedApplication] presentLocalNotificationNow:localNotification];
    }
  }

我的错误在哪里？

修改

displayHistory()

Answer 1

- (void)xmppStream:(XMPPStream *)sender didReceiveMessage:(XMPPMessage*)message
{
//in this the (XMPPMessage*)message parameter is xml data
//parse you xml and create dictionary For eg : sampledict
}

通常，当您收到XMPP的回复时，它就像XML数据一样。您必须解析并用于您的操作。

在你的代码中

if ([[UIApplication sharedApplication] applicationState] == UIApplicationStateActive)
{
   // UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:displayName
                                                        message:body
                                                       delegate:nil
                                              cancelButtonTitle:@"Ok"
                                              otherButtonTitles:nil];
   // [alertView show];
}
else
{
    // We are not active, so use a local notification instead
    UILocalNotification *localNotification = [[UILocalNotification alloc] init];
    localNotification.alertAction = @"Ok";
    localNotification.alertBody = [NSString stringWithFormat:@"From: %@\n\n%@",displayName,body];

    [[UIApplication sharedApplication] presentLocalNotificationNow:localNotification];
}

您使用过alertview。因此，您必须隐藏您的提醒视图，以便您不会收到提醒。而是管理您的观察者方法以获取数据并使用它

-(void)messageReceived:(NSNotification*)notif
{ 
XMPPMessage *message=(XMPPMessage*)notif.object;
NSString *body = [[message elementForName:@"body"] stringValue];
NSMutableDictionary *dic_recive = [[NSMutableDictionary alloc]init];
[dic_recive setObject:body forKey:@"text"];
[data addObject:dic_recive];
chatLblRight = 1;
[tblobj reloadData];
}

我认为这会对你有帮助..

Answer 2

你需要在uitableviewcellforrowatindexpath方法中设置你的逻辑。

 - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
UITableViewCell *cell = [tblobj dequeueReusableCellWithIdentifier:@"cell"];
UILabel *lbl;
if (cell==nil)
{
    cell = [[UITableViewCell alloc]initWithStyle:UITableViewCellStyleDefault reuseIdentifier:@"cell"];

    if([[[data objectAtIndex:indexPath.row]valueForKey:@"type"] isEqualToString:@"2"])
    //if (chatLblRight == 1)
    {
        lbl = [[UILabel alloc]initWithFrame:CGRectMake(200, 10, 150, 44)];
        [lbl setTextColor:[UIColor redColor]];
        [cell.contentView   addSubview:lbl];
    }


}
if([[[data objectAtIndex:indexPath.row]valueForKey:@"type"] isEqualToString:@"2"])

//if([[[data objectAtIndex:indexPath.row]valueForKey:@"type"] isEqualToString:@"1"])
//if (chatLblRight == 1)
{
    lbl.text = [[data objectAtIndex:indexPath.row]valueForKey:@"text"];
    chatLblRight = 0;
    lbl = [[UILabel alloc]initWithFrame:CGRectMake(200, 10, 150, 44)];
    [lbl setTextColor:[UIColor redColor]];
    [cell.contentView   addSubview:lbl];

    return cell;
}
else
{
    cell.textLabel.text=[[data objectAtIndex:indexPath.row]valueForKey:@"text"];
    return cell;
  }

}

请检查此代码一次。

Answer 3

请转到xmpp自定义类并发布此类通知

- (void)xmppStream:(XMPPStream *)sender didReceiveMessage:(XMPPMessage *)message
{
//parse you xml and create dictionary For eg : sampledict
NSNotificationCenter *notificationCenter = [NSNotificationCenter defaultCenter];
                        [notificationCenter postNotificationName:@"updateValue" object:nil userInfo:sampledict];

}

并接收来自您班级的通知使用像

这样的通知

[[NSNotificationCenter defaultCenter] addObserver:self
                                             selector:@selector(receiveUpdatedValues:)
                                                 name:@"updateValue"
                                               object:nil];


-(void)receiveUpdatedValues : (NSNotification *)notification
{
NSDictionary *dictinfo=notification.userInfo;
// here use your info dict to get your message
}

iOS XMPP在对话屏幕中收到消息

3 个答案: