如何更新多行php

时间:2015-06-15 10:03:38

标签: php

我想更新多行

这是我的HTML代码:

<form action="" method="POST">
<input type="text" name="name" placeholder=""/>
<input type="text" name="phone" placeholder=""/>
<input type="text" name="blood" placeholder=""/>
<input type="text" name="id" placeholder=""/>
<input type="text" name="email" placeholder=""/>
<input type="submit" name="sub" value=""/>
</form>

这是我的PHP代码:

  if(isset($_POST['sub'])) {
    $name = $_POST['name'];
    $phone = $_POST['phone'];
    $blood = $_POST['blood'];
    $id = $_POST['id'];
    $email = $_POST['email'];
    if($name or $phone or $blood or $id or $email) {
      $res_11 = mysql_query("UPDATE `general_info` SET `name`='$name',`phone`='$phone',`blood`='$blood',`id_2`='$id',`email`='$email'  WHERE `id`='1'") or die(mysql_error());
    }
  }else{
    echo "ERROR";
  }

我有这样的表

name | phone | blood

我希望如果某个机构只更新一行更新

如果只是新手机更新只是手机在数据库中

2 个答案:

答案 0 :(得分:1)

试用此代码:

 if(isset($_POST['sub'])) {
     $subQuery = "";
     if(isset($_POST['name']) && $_POST['name'] != "") {
         $subQuery .= " name = '". $_POST['name'] ."',";
                $name = $_POST['name'];
     }
     if(isset($_POST['phone']) && $_POST['phone'] != "") {
         $subQuery .= " phone = '". $_POST['phone'] ."',";
                 $phone = $_POST['phone'];
     }
     if(isset($_POST['blood']) && $_POST['blood'] != "") {
         $subQuery .= " blood = ". $_POST['blood'] .",";
                 $blood = $_POST['blood'];
     }

     if(isset($_POST['email']) && $_POST['email'] != "") {
         $subQuery .= " email= '". $_POST['email'] ."',";
                 $email = $_POST['email'];
     }
     if(isset($_POST['id']) && $_POST['id'] != "") {
         $subQuery .= " id_2 = '". $_POST['id'] ."',";
                 $id = $_POST['id'];
     }

    if($name or $phone or $blood or $id or $email) {
      $res_11 = mysql_query("UPDATE `general_info` SET ". substr($subQuery, 0, -1) ."  WHERE `id`='1'") or die(mysql_error());
    }
  }else{
    echo "ERROR";
  }

答案 1 :(得分:0)

我认为这就是你想要做的。但是不要使用 mysql 使用PDO或mysqli。     

x+3
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