我在我的桌面上使用bootstrap和Datatables.net来集成搜索和分页。问题是在单击提交按钮后,只有表的当前页面保留在模型上。
如果没有通过Datatables.net集成搜索和分页,只有在使用Datatables.net插件时才会出现错误。
型号:
public class SampleViewModel
{
public List<CollectionViewModel> Collection { get; set; }
}
public class CollectionViewModel
{
public string Name { get; set; }
public int? Value { get; set; }
}
控制器:
public ActionResult Sample()
{
SampleViewModel model = new SampleViewModel();
model.Collection = new List<CollectionViewModel>();
model.Collection.Add(new CollectionViewModel { Name = "Test1" });
model.Collection.Add(new CollectionViewModel { Name = "Test2" });
model.Collection.Add(new CollectionViewModel { Name = "Test3" });
model.Collection.Add(new CollectionViewModel { Name = "Test4" });
model.Collection.Add(new CollectionViewModel { Name = "Test5" });
model.Collection.Add(new CollectionViewModel { Name = "Test6" });
model.Collection.Add(new CollectionViewModel { Name = "Test7" });
model.Collection.Add(new CollectionViewModel { Name = "Test8" });
model.Collection.Add(new CollectionViewModel { Name = "Test9" });
model.Collection.Add(new CollectionViewModel { Name = "Test10" });
model.Collection.Add(new CollectionViewModel { Name = "Test11" });
model.Collection.Add(new CollectionViewModel { Name = "Test12" });
model.Collection.Add(new CollectionViewModel { Name = "Test13" });
model.Collection.Add(new CollectionViewModel { Name = "Test14" });
model.Collection.Add(new CollectionViewModel { Name = "Test15" });
return View(model);
}
[HttpPost]
public ActionResult Sample(SampleViewModel model)
{
var ctr = model.Collection.Count(x => x.Value != null);
return View(model);
}
查看:
@model MyApp.Models.SampleViewModel
@using (Html.BeginForm())
{
<div class="dataTable_wrapper">
<div class="pull-right">
<button type="submit" name="submitButton" class="btn btn-primary btn-sm">
<i class="fa fa-floppy-o fa-1x"></i>
Submit
</button>
</div><br /><hr />
<table class="table table-striped table-bordered table-hover">
<thead>
<tr>
<th>Name</th>
<th>Value</th>
</tr>
</thead>
<tbody>
@for (int i = 0; i < Model.Collection.Count(); ++i)
{
@Html.HiddenFor(model => model.Collection[i].Name)
<tr>
<td>@Html.DisplayFor(model => model.Collection[i].Name)</td>
<td>
@Html.TextBoxFor(model => model.Collection[i].Value, new { @class = "form-control" })
</td>
</tr>
}
</tbody>
</table>
</div>
}
提交前:
点击提交按钮后
您可以在上面的图片中看到,代替 15条记录,只有 10条记录存储在模型上。
答案 0 :(得分:1)
当使用带分页的DataTables插件时,DOM中仅存在当前页面<tr>
元素(示例中为10
)以提高性能。因此,当您提交表单时,仅提交当前页面表单控件值。
诀窍是在提交表单之前将表单元素从当前页面转换为<input type="hidden">
。
var table = $('#example').DataTable();
// Handle form submission event
$('#frm-example').on('submit', function(e){
var form = this;
// Encode a set of form elements from all pages as an array of names and values
var params = table.$('input,select,textarea').serializeArray();
// Iterate over all form elements
$.each(params, function(){
// If element doesn't exist in DOM
if(!$.contains(document, form[this.name])){
// Create a hidden element
$(form).append(
$('<input>')
.attr('type', 'hidden')
.attr('name', this.name)
.val(this.value)
);
}
});
});
请参阅this example以获取代码和演示。
另一种解决方案是通过Ajax提交表单。
var table = $('#example').DataTable();
// Handle form submission event
$('#frm-example').on('submit', function(e){
// Prevent actual form submission
e.preventDefault();
// Serialize form data
var data = table.$('input,select,textarea').serialize();
// Submit form data via Ajax
$.ajax({
url: '/echo/jsonp/',
data: data,
success: function(data){
console.log('Server response', data);
}
});
});
请参阅this example以获取代码和演示。
请注意,这两种解决方案仅适用于客户端处理模式。
有关详细信息,请参阅jQuery DataTables: How to submit all pages form data。