Question

我正试图在Java中播放基本声音......

这是我的代码，基于各种论坛上的代码：

    Clip clip = null;

    try {
        clip = AudioSystem.getClip();
        AudioInputStream inputStream = AudioSystem.getAudioInputStream(new File(url));
        clip.open(inputStream);
    } catch (LineUnavailableException | IOException | UnsupportedAudioFileException ex) {
        Logger.getLogger(Pomodoro.class.getName()).log(Level.SEVERE, null, ex);
    }

    return clip;

我检查过：new File(url).exists();返回true，我检查文件类型是否真的是音频WAV（audio / x-wav），我检查了问题是否仍存在于另一个文件中......我不明白我做错了什么。

错误：

Exception in thread "main" java.lang.ExceptionInInitializerError
Caused by: java.lang.IllegalArgumentException: Invalid format
    at org.classpath.icedtea.pulseaudio.PulseAudioDataLine.createStream(PulseAudioDataLine.java:142)
    at org.classpath.icedtea.pulseaudio.PulseAudioDataLine.open(PulseAudioDataLine.java:99)
    at org.classpath.icedtea.pulseaudio.PulseAudioDataLine.open(PulseAudioDataLine.java:283)
    at org.classpath.icedtea.pulseaudio.PulseAudioClip.open(PulseAudioClip.java:402)
    at org.classpath.icedtea.pulseaudio.PulseAudioClip.open(PulseAudioClip.java:453)

帮助！

Answer 1

我终于找到了我的问题的副本。对不起我打扰了你。

AudioInputStream is not working

我的代码变成了：

    Clip clip = null;

    try {
        AudioInputStream inputStream = AudioSystem.getAudioInputStream(new File(url));
        DataLine.Info info = new DataLine.Info(Clip.class, inputStream.getFormat());
        clip = (Clip)AudioSystem.getLine(info);
        clip.open(inputStream);
    } catch (LineUnavailableException | IOException | UnsupportedAudioFileException ex) {
        Logger.getLogger(Pomodoro.class.getName()).log(Level.SEVERE, null, ex);
    }

    return clip;

然而，我很惊讶我以前的代码没有用。有时，我非常渴望Java ......

Answer 2

您可以使用以下代码在Java中播放声音。

   try {
        DataLine.Info daInfo = new DataLine.Info(Clip.class, null);
        try {
            URL sounURL = ClassName.class.getResource("/com/notification.wav");

            AudioInputStream inputStream = AudioSystem.getAudioInputStream(sounURL);
            DataLine.Info info = new DataLine.Info(Clip.class, inputStream.getFormat());
            Clip clip = (Clip) AudioSystem.getLine(info);
            clip.open(inputStream);
            clip.start();
        } catch (LineUnavailableException e) {
            e.printStackTrace();
        } catch (UnsupportedAudioFileException ex) {
            ex.printStackTrace();
        } catch (IOException ex) {
            ex.printStackTrace();
        }
    } catch (Exception e) {
        System.out.println("music");
    }

getAudioInputStream的格式无效，试图用Java播放声音

2 个答案: