我最近遇到了这个问题:
我有:directive-b
,element = $compile('<directive-a></directive-a>')($scope);
指令-b有一个`要求:&#39; ^指令-a&#39;使单元测试无法进行的领域。
我曾经在单元测试中以这种方式编译指令:
element.isolateScope()
然后我可以使用element = $compile('<directive-a> <directive-b></directive-b> </directive-a>')($scope);
但是现在因为b依赖于a,我必须这样做:
element.isolateScope()
在这种情况下,directive-b
返回指令-a的范围而不是指令-b。
如何获得(function(){
'use strict';
function directiveA(){
return {
restrict: 'E',
templateUrl: '/main/templates/directiveA.html',
transclude: true,
scope: {
attr1: '='
},
controller: function($scope){
//code...
},
link: function($scope, element, attrs, ctrl, transclude){
injectContentIntoTemplate();
function injectContentIntoTemplate(){
transclude(function (clone) {
element.find('#specificElement').append(clone);
});
}
}
};
}
angular
.module('myModule')
.directive('directiveA', directiveA);
}());
的范围?
演示:
指令A:
(function(){
'use strict';
function directiveB(){
return {
restrict: 'E',
templateUrl: '/main/templates/directiveA.html',
transclude: true,
replace: true,
scope: {
attr1: '@'
},
require: '^directiveA',
link: function ($scope, element, attrs, ctrl) {
$scope.customVariable = 'something';
}
};
}
angular
.module('myModule')
.directive('directiveB', directiveB);
}());
指令B:
switch (oldVersion) {
case 1: upgradeFromV1();
case 2: upgradeFromV2();
case 3: upgradeFromV3();
}
答案 0 :(得分:0)
迟到的答案,未经测试。
let element = $compile('<directive-a> <directive-b></directive-b> </directive-a>')($scope);
let elementB = element.find('directive-b');
let BsScope = elementB.isolateScope();