Question

如何在

之间添加更多单词

if(inputText!.text == "motorka"){

我想添加“Motorka”和“MOTORKA”。但以下不起作用：

if(inputText!.text == "motorka", "Motorka", "MOTORKA"){

如何查看超过一个字符串？

override func touchesBegan(touches: Set<NSObject>, withEvent event: UIEvent) {
  let touch = touches.first as! UITouch
  let touchLocation = touch.locationInNode(self)
  let touchedNode = self.nodeAtPoint(touchLocation)

  if(touchedNode.name == "checkbutton"){
    if(inputText!.text == "motorka"){
      runAction(SKAction.playSoundFileNamed("correct.wav", waitForCompletion: false))
      correct.hidden = false
      inputText!.hidden = true
      check.hidden = true
      let nextLevel = level2(size: size)
      nextLevel.scaleMode = scaleMode
      let transitionType = SKTransition.crossFadeWithDuration(1.4)
      let wait = SKAction.waitForDuration(0.9)
      let action = SKAction.runBlock {
        view?.presentScene(nextLevel, transition: transitionType)
      }
      self.runAction(SKAction.sequence([wait, action]))
    }
}

Answer 1

您是否在寻找布尔值OR ||：

if(inputText!.text == "motorka" || inputText!.text == "Motorka" || inputText!.text == "MOTORKA") { ... }

但是为了使它看起来更好并且在某些情况下更高效，你应该为文本创建一个临时变量，然后对该变量运行检查：

let text = inputText!.text
if(text == "motorka" || text == "Motorka" || text == "MOTORKA") { ... }

您甚至可能想要同时删除OR，并使用lowercaseString个属性，它将匹配单词"motorka"的每个大/小写变体：

let text = inputText!.text.lowercaseString
if(text == "motorka") { ... }

Answer 2

使用NSArray和containsObject：

let text = inputText!.text
let wordList = ["motorka", "Motorka", "MOTORKA"] as NSArray
if wordList.containsObject(text) {
    ...
}

inputText中的更多单词

2 个答案: