Question

我想从特定字段中删除引号之间存在整数的引号。

从这一行："AAA","99"

到这一行："AAA",99

Answer 1

使用sed：

s='"AAA","99"'
sed 's/"\([0-9]*\)"/\1/g' <<< "$s"
"AAA",99

Answer 2

尝试使用GNU sed：

echo '"AAA","99"' | sed -E 's/"([0-9]+)"$/\1/'

输出：

"AAA",99

Answer 3

使用awk：

awk -F , 'BEGIN { OFS = FS } $2 ~ /^"[0-9]+"$/ { gsub(/"/, "", $2) } 1'

其工作原理如下：

BEGIN { OFS = FS }  # Delimit output the same way as the input

$2 ~ /^"[0-9]+"$/ { # if the second field ($2) consists of only numbers encased
                    # by double quotes (i.e., matches the regex ^"[0-9]"$)
  gsub(/"/, "", $2) # remove the quotes from it
}
1                   # print in any case

要使其适用于任何（而不仅仅是特定字段），请在循环中进行替换：

awk -F , 'BEGIN { OFS = FS } { for(i = 1; i <= NF; ++i) if($i ~ /^"[0-9]+"$/) { gsub(/"/, "", $i) } } 1'

此处更改的位是

{                              # Do this unconditionally in every line:
  for(i = 1; i <= NF; ++i) {   # wade through all the fields
    if($i ~ /^"[0-9]+"$/) {    # then do with them the same thing as before.
      gsub(/"/, "", $i)
    }
  }
}

从特定字段中删除引号 - 引号之间的整数

3 个答案: