我使用以下方式提取用户:
library(plyr)
res <- dlply(dat, .(Group), function(x) unique(x$Name))
res[["4"]]
# [1] B E
# Levels: A B C D E
## If you want to extract all the groups with a "B" Name
inds <- unlist(lapply(res, function(x) "B" %in% x))
inds
# 1 2 3 4
# FALSE FALSE FALSE TRUE
## and to extract that Group
names(inds)[inds]
# [1] "4"
这是用户模型:
var user = this.store.find('user', user_id);
我试图运行一个之前的模型,我检查用户是否是管理员,然后做一些事情,如果它的真或假,例如:
export default DS.Model.extend({
username: DS.attr('string'),
email: DS.attr('string'),
first_name: DS.attr('string'),
last_name: DS.attr('string'),
password: DS.attr('string'),
is_admin: DS.attr('boolean')
});
我也尝试过这样做:
beforeModel: function(){
var user = this.store.find('user', 1);
if(user.get('is_admin')){
return 'do something since they are an admin';
}
},
如何在路线中获取beforeModel: function(){
var user = this.store.find('user', 1);
return user.then(function(response){
if(response.is_admin){
return 'do something since they are an admin';
}
});
},
属性?
答案 0 :(得分:0)
您可以在路线中定义isAdmin
属性,并在user
承诺解决时设置。
//route
isAdmin: false,
beforeModel: function() {
var self = this;
return this.store.find('user', 1).then(function(user){
self.set('isAdmin', user.get('is_admin'));
}, function(){
// on reject
})
}