我的问题与this one类似,但在我的理解中却有所不同。
我有三张桌子:
Units ([UnitID] int, [UnitParentID] int)
Students ([StudentID] int, [UnitID] int)
Events ([EventID] int, [EventTypeID] int, [StudentID] int)
Students
属于单位,单位以层次结构堆叠(树形式 - 每个孩子一个父母),每个学生可以有不同类型的事件。
我需要总结每个用户每种类型的事件数,然后汇总一个单元中的所有用户,然后通过层次结构聚合,直到我到达所有单位的母亲。
结果应该是这样的:
我的工具是SQL Server 2008和Report Builder 3。 为了好玩,我提供了一个SQL fiddle样本数据。
答案 0 :(得分:3)
使用此查询:
;WITH CTE(Id, ParentId, cLevel, Title, ord) AS (
SELECT
u.UnitID, u.UnitParentID, 1,
CAST('Unit ' + CAST(ROW_NUMBER() OVER (ORDER BY u.UnitID) AS varchar(3)) AS varchar(max)),
CAST(RIGHT('000' + CAST(ROW_NUMBER() OVER (ORDER BY u.UnitID) AS varchar(3)), 3) AS varchar(max))
FROM
dbo.Units u
WHERE
u.UnitParentID IS NULL
UNION ALL
SELECT
u.UnitID, u.UnitParentID, c.cLevel + 1,
c.Title + '.' + CAST(ROW_NUMBER() OVER (PARTITION BY c.cLevel ORDER BY c.Id) AS varchar(3)),
c.ord + RIGHT('000' + CAST(ROW_NUMBER() OVER (ORDER BY u.UnitID) AS varchar(3)), 3)
FROM
dbo.Units u
JOIN
CTE c ON c.Id = u.UnitParentID
WHERE
u.UnitParentID IS NOT NULL
), Units AS (
SELECT
u.Id, u.ParentId, u.cLevel, u.Title, u.ord,
SUM(CASE WHEN e.EventTypeId = 1 THEN 1 ELSE 0 END) AS EventA,
SUM(CASE WHEN e.EventTypeId = 2 THEN 1 ELSE 0 END) AS EventB,
SUM(CASE WHEN e.EventTypeId = 3 THEN 1 ELSE 0 END) AS EventC,
SUM(CASE WHEN e.EventTypeId = 4 THEN 1 ELSE 0 END) AS EventD
FROM
CTE u
LEFT JOIN
dbo.Students s ON u.Id = s.UnitId
LEFT JOIN
dbo.[Events] e ON s.StudentId = e.StudentId
GROUP BY
u.Id, u.ParentId, u.cLevel, u.Title, u.ord
), addStudents AS (
SELECT *
FROM Units
UNION ALL
SELECT
s.StudentId, u.Id, u.cLevel + 1,
'Student ' + CAST(s.StudentId AS varchar(3)),
u.ord + RIGHT('000' + CAST(s.StudentId AS varchar(3)), 0),
SUM(CASE WHEN e.EventTypeId = 1 THEN 1 ELSE 0 END),
SUM(CASE WHEN e.EventTypeId = 2 THEN 1 ELSE 0 END),
SUM(CASE WHEN e.EventTypeId = 3 THEN 1 ELSE 0 END),
SUM(CASE WHEN e.EventTypeId = 4 THEN 1 ELSE 0 END)
FROM Units u
JOIN
dbo.Students s ON u.Id = s.UnitId
LEFT JOIN
dbo.[Events] e ON s.StudentId = e.StudentId
GROUP BY
s.StudentID, u.ID, u.cLevel, u.ord
)
SELECT --TOP(10)
REPLICATE(' ', cLevel) + Title As Title,
EventA, EventB, EventC, EventD
FROM
addStudents
ORDER BY
ord
为此:
Title | EventA | EventB | EventC | EventD
-----------------+--------+---------+--------+--------
Unit 1 | 0 | 1 | 0 | 0
Student 6 | 0 | 1 | 0 | 0
Unit 1.1 | 0 | 0 | 0 | 1
Student 21 | 0 | 0 | 0 | 1
Student 33 | 0 | 0 | 0 | 0
Unit 1.1.1 | 0 | 0 | 0 | 0
Student 23 | 0 | 0 | 0 | 0
Unit 1.1.1.1 | 3 | 2 | 3 | 0
Student 10 | 0 | 0 | 0 | 0
Student 17 | 1 | 0 | 0 | 0
...
答案 1 :(得分:1)
您是否还需要对层次结构进行排序/可视化?至少这将计算总和,但数据的顺序非常随机:)
;with CTE as (
select S.StudentId as UnitID, S.UnitId as UnitParentID,
S.StudentID, 'Student' as Type
from Students S
union all
select U.UnitId, U.UnitParentId,
CTE.StudentId as StudentID, 'Unit ' as Type
from
Units U
join CTE
on U.UnitId = CTE.UnitParentId
)
select C.Type + ' ' + convert(varchar, C.UnitId),
sum(case when EventTypeId = 1 then 1 else 0 end) as E1,
sum(case when EventTypeId = 2 then 1 else 0 end) as E2,
sum(case when EventTypeId = 3 then 1 else 0 end) as E3,
sum(case when EventTypeId = 4 then 1 else 0 end) as E4
from
CTE C
left outer join events E on C.StudentId = E.StudentId
group by
C.Type, C.UnitId
如果您还需要层次结构,那么您可能需要添加一些额外的CTE来自上而下使用@ shA.t这样的编号。这会为每个学生单独收集层次结构,因此无法以简单的方式添加级别编号。