Question

我有一份我想要的库存单位和销售交易清单，（1）按单位SKU加入，以及（2）按日期先进先出顺序将一笔交易与一个库存单位关联。我在第二部分遇到了麻烦。

我能想到的最好的是：

SELECT `units`.`unit_date`, `units`.`unit_id`, `trans`.`tran_date`, `trans`.`tran_id`, `units`.`unit_sku` FROM `units`
    INNER JOIN `trans`
        ON `trans`.`unit_sku` = `units`.`unit_sku`
GROUP BY `trans`.`tran_id`, `trans`.`unit_sku`
ORDER BY `units`.`unit_date` asc, `trans`.`tran_date` asc
;

units表：

unit_date  | unit_id | unit_sku
2015-06-01 | 1       | U1KLM
2015-06-02 | 2       | U1KLM
2015-06-03 | 3       | U2QRS
2015-06-04 | 4       | U2QRS
2015-06-05 | 5       | U1KLM

trans表：

tran_date  | tran_id | unit_sku
2015-06-11 | A       | U2QRS
2015-06-12 | B       | U1KLM
2015-06-13 | C       | U1KLM
2015-06-14 | D       | U2QRS
2015-06-15 | E       | U1KLM

期望的结果是tran_id一个unit_id加入unit_sku unit_date的最早到最新订单unit_date | unit_id | tran_date | tran_id | unit_sku 2015-06-01 | 1 | 2015-06-12 | B | U1KLM 2015-06-02 | 2 | 2015-06-13 | C | U1KLM 2015-06-03 | 3 | 2015-06-11 | A | U2QRS 2015-06-04 | 4 | 2015-06-14 | D | U2QRS 2015-06-05 | 5 | 2015-06-15 | E | U1KLM ：

tran_id

查询（不受欢迎）结果仅将unit_id加入unit_sku最早出现的unit_date | unit_id | tran_date | tran_id | unit_sku 2015-06-01 | 1 | 2015-06-12 | B | U1KLM 2015-06-01 | 1 | 2015-06-13 | C | U1KLM 2015-06-01 | 1 | 2015-06-15 | E | U1KLM 2015-06-03 | 3 | 2015-06-11 | A | U2QRS 2015-06-03 | 3 | 2015-06-14 | D | U2QRS：

unit_date

有关如何获得所需结果的任何想法？在此设置中，只有tran_date和DROP TEMPORARY TABLE IF EXISTS `units`; DROP TEMPORARY TABLE IF EXISTS `trans`; CREATE TEMPORARY TABLE `units` (`unit_date` date, `unit_id` char(1) , `unit_sku` char(5), PRIMARY KEY(`unit_id`)); CREATE TEMPORARY TABLE `trans` (`tran_date` date, `tran_id` char(1) , `unit_sku` char(5), PRIMARY KEY(`tran_id`)); INSERT INTO `units` (`unit_date`, `unit_id`, `unit_sku`) VALUES ('2015-06-01', '1', 'U1KLM') , ('2015-06-02', '2', 'U1KLM') , ('2015-06-03', '3', 'U2QRS') , ('2015-06-04', '4', 'U2QRS') , ('2015-06-05', '5', 'U1KLM') ; INSERT INTO `trans` (`tran_date`, `tran_id`, `unit_sku`) VALUES ('2015-06-11', 'A', 'U2QRS') , ('2015-06-12', 'B', 'U1KLM') , ('2015-06-13', 'C', 'U1KLM') , ('2015-06-14', 'D', 'U2QRS') , ('2015-06-15', 'E', 'U1KLM') ; SELECT `units`.`unit_date`, `units`.`unit_id`, `trans`.`tran_date`, `trans`.`tran_id`, `units`.`unit_sku` FROM `units` INNER JOIN `trans` ON `trans`.`unit_sku` = `units`.`unit_sku` GROUP BY `trans`.`tran_id`, `trans`.`unit_sku` ORDER BY `units`.`unit_date` asc, `trans`.`tran_date` asc ;可以排序;其余的是随机生成的。

Repro脚本：

to_representation()

Answer 1

我相信这就是你要找的东西:(这是假设1比1的关系）

SET @UNITRN := 0;
SET @TRANSRN :=0;
SELECT A.`unit_date`, A.`unit_id`, B.`tran_date`, B.`tran_id`, A.`unit_sku` FROM (SELECT @UNITRN := @UNITRN + 1 AS ROWNUM, UNIT_DATE, UNIT_ID, UNIT_SKU FROM UNITS ORDER BY UNIT_SKU, UNIT_DATE ASC) A
JOIN (SELECT @TRANSRN := @TRANSRN + 1 AS ROWNUM, TRAN_DATE, TRAN_ID, UNIT_SKU FROM TRANS ORDER BY UNIT_SKU, TRAN_DATE ASC) B
ON A.UNIT_SKU = B.UNIT_SKU
AND A.ROWNUM = B.ROWNUM
ORDER BY A.UNIT_DATE ASC

MySQL：按特定顺序加入两个表的不同行？

1 个答案: