Question

我知道如何在不使用类的情况下显示数据，但我被要求使用mysql类。似乎我必须启动课程并只使用书面函数，但无论我试图显示什么 - 它都不起作用。我得到的只是“资源ID＃14”，这意味着一切都应该与连接良好。请帮忙！

这是MySQL类的一部分：

class SQL //MySQL
{
  var $link_id;
  var $query_result;
  var $num_queries = 0;

  function connect($db_host, $db_username, $db_password, $db_name = '', $use_names = '', $pconnect = false, $newlink = true) {

    if ($pconnect) $this->link_id = @mysql_pconnect($db_host, $db_username, $db_password);
    else $this->link_id = @mysql_connect($db_host, $db_username, $db_password, $newlink);
        if (!empty($use_names)) $this->query("SET NAMES '$use_names'");

    if ($this->link_id){
      if($db_name){
        if (@mysql_select_db($db_name, $this->link_id)) return $this->link_id;
          else die(mysql_error());// = "Can't open database ('$db_name')";
        if (!empty($use_names)) $this->query("SET NAMES '$use_names'");
      }
    } else die(mysql_error());// = "Can't connect to mysql server";
  }

  function db($db_name) {
    if ($this->link_id){
      if (@mysql_select_db($db_name, $this->link_id)) return $this->link_id;
        else die(mysql_error());// = "Can't open database ('$db_name')";
    } else die(mysql_error());// = "Can't connect to database";
  }

  function query($sql){
    $this->query_result = @mysql_query($sql, $this->link_id);

    if ($this->query_result){
      ++$this->num_queries;
      return $this->query_result;
    } else {
        $error = "
            <pre>
                QUERY: \n {$sql} \n\n
                ERROR: <span style=\"color:red\">" . mysql_error() . " </span>
            </pre>
        ";
      die($error);
    }
  }
  function result($query_id = 0, $row = 0, $field = NULL){
    return ($query_id) ? @mysql_result($query_id, $row, $field) : false;
  }

  function fetch_row($query_id = 0){
    return ($query_id) ? @mysql_fetch_row($query_id) : false;
  }

  function fetch_array($query_id = 0){
    return ($query_id) ? @mysql_fetch_array($query_id) : false;
  }

  function fetch_assoc($query_id = 0){
    return ($query_id) ? @mysql_fetch_assoc($query_id) : false;
  }

  function num_rows($query_id = 0){
    return ($query_id) ? @mysql_num_rows($query_id) : false;
  }
....

和我的PHP代码：

<?php
require_once('C:/wamp/www/smarty-3.1.21/libs/Smarty.class.php');
include('C:/wamp/www/smarty-3.1.21/libs/Mysql.class.php');

$smarty = new Smarty();
$smarty->enableSecurity();

$smarty->setTemplateDir('C:\wamp\www\forum\templates');
$smarty->setCompileDir('C:\wamp\www\forum\templates_c');
$smarty->setConfigDir('C:\wamp\www\forum\configs');
$smarty->setCacheDir('C:\wamp\www\forum\cache');

$db = new SQL();
$db->connect('localhost','root','','job', '', false, true);

$db->db('job');
$sql = "SELECT * FROM job";
$db->query($sql);
$output = $db->query_result;
$result = $db->fetch_row();


$smarty->assign('rez', $result);
$smarty->assign('output', $output);
$smarty->display('index.tpl');

?>

在PHP中使用MySQL类显示数据

0 个答案: