在我的程序中,多个线程(检查器)请求网页,如果这些页面包含一些数据,则另一个线程(消费者)处理数据。我只需要预定义的消费者数来开始处理(不是全部)。我尝试使用std :: atomic counter和fetch_add来限制工作的消费者数量。但是,虽然计数器保持在一定范围内,但消费者获得相同的计数器值,并且实际处理消费者数量超过限制行为取决于处理持续时间。简化代码包含sleep_for,而不是获取页面和处理页面功能。
#include <iostream>
#include <thread>
#include <atomic>
#include <chrono>
class cConsumer
{
public:
cConsumer::cConsumer(
const size_t aNumber,
std::atomic<bool> &aFire,
std::atomic<size_t> &aCounter) :
mNumber(aNumber),
mFire(aFire),
mCounter(aCounter){}
void cConsumer::operator ()()
{
while (true)
{
while (!mFire.load()) std::this_thread::sleep_for(mMillisecond);
size_t vCounter = mCounter.fetch_add(1);
if (vCounter < 5)
{
std::cout << " FIRE! consumer " << mNumber << ", counter " << vCounter << "\n";
std::this_thread::sleep_for(mWorkDuration);
}
if (vCounter == 5)
{
mFire.store(false);
mCounter.store(0);
}
}
}
private:
static const std::chrono::milliseconds
mMillisecond,
mWorkDuration;
const size_t mNumber;
std::atomic<bool> &mFire;
std::atomic<size_t> &mCounter;
};
const std::chrono::milliseconds
cConsumer::mMillisecond(1),
cConsumer::mWorkDuration(1300);
class cChecker
{
public:
cChecker(
const size_t aNumber,
std::atomic<bool> &aFire) :
mNumber(aNumber),
mFire(aFire),
mStep(1){ }
void cChecker::operator ()()
{
while (true)
{
while (mFire.load()) std::this_thread::sleep_for(mMillisecond);
std::cout << "checker " << mNumber << " step " << mStep << "\n";
std::this_thread::sleep_for(mCheckDuration);
if (mStep % 20 == 1) mFire.store(true);
mStep++;
}
}
private:
static const std::chrono::milliseconds
mMillisecond,
mCheckDuration;
const size_t mNumber;
size_t mStep;
std::atomic<bool> &mFire;
};
const std::chrono::milliseconds
cChecker::mMillisecond(1),
cChecker::mCheckDuration(500);
void main()
{
std::atomic<bool> vFire(false);
std::atomic<size_t> vCounter(0);
std::thread vConsumerThreads[16];
for (size_t i = 0; i < 16; i++)
{
std::thread vConsumerThread((cConsumer(i, vFire, vCounter)));
vConsumerThreads[i] = std::move(vConsumerThread);
}
std::chrono::milliseconds vNextCheckerDelay(239);
std::thread vCheckerThreads[3];
for (size_t i = 0; i < 3; i++)
{
std::thread vCheckerThread((cChecker(i, vFire)));
vCheckerThreads[i] = std::move(vCheckerThread);
std::this_thread::sleep_for(vNextCheckerDelay);
}
for (size_t i = 0; i < 16; i++) vConsumerThreads[i].join();
for (size_t i = 0; i < 3; i++) vCheckerThreads[i].join();
}
输出示例(部分)
...
checker 1 step 19
checker 0 step 20
checker 2 step 19
checker 1 step 20
checker 0 step 21
checker 2 step 20
checker 1 step 21
FIRE! consumer 10, counter 0
FIRE! consumer 13, counter 4
FIRE! consumer 6, counter 1
FIRE! consumer 0, counter 2
FIRE! consumer 2, counter 3
checker 0 step 22
checker 2 step 21
FIRE! consumer 5, counter 3
FIRE! consumer 7, counter 4
FIRE! consumer 4, counter 1
FIRE! consumer 15, counter 2
FIRE! consumer 8, counter 0
checker 1 step 22
FIRE! consumer 9, counter 0
FIRE! consumer 11, counter 1
FIRE! consumer 3, counter 2
FIRE! consumer 14, counter 3
FIRE! consumer 1, counter 4
checker 0 step 23
checker 2 step 22
checker 1 step 23
checker 2 step 23
checker 0 step 24
checker 1 step 24
我找到了一个有效但不优雅的解决方案:等待所有消费者尝试工作并了解火灾已经消失。
#include <iostream>
#include <thread>
#include <atomic>
#include <chrono>
class cConsumer
{
public:
cConsumer::cConsumer(
const size_t aNumber,
const size_t aConsumerCount,
std::atomic<bool> &aFire,
std::atomic<size_t> &aCounter) :
mNumber(aNumber),
mConsumerCount(aConsumerCount),
mFire(aFire),
mCounter(aCounter){}
void cConsumer::operator ()()
{
while (true)
{
while (!mFire.load()) std::this_thread::sleep_for(mMillisecond);
const size_t vCounter = mCounter.fetch_add(1);
if (vCounter < 5)
{
std::cout << " FIRE! consumer " << mNumber << ", counter " << vCounter << "\n";
std::this_thread::sleep_for(mWorkDuration); //stub for process function
}
if (vCounter >= 5)
{
std::this_thread::sleep_for(mWorkDuration); //wait for other threads to increase counter
std::this_thread::sleep_for(mWorkDuration); //double wait for long processing
mFire.store(false);
}
if (vCounter == mConsumerCount)
{
mCounter.store(0);
}
}
}
private:
static const std::chrono::milliseconds
mMillisecond,
mWorkDuration;
const size_t
mNumber,
mConsumerCount;
std::atomic<bool> &mFire;
std::atomic<size_t> &mCounter;
};
const std::chrono::milliseconds
cConsumer::mMillisecond(1),
cConsumer::mWorkDuration(1300);
class cChecker
{
public:
cChecker(
const size_t aNumber,
std::atomic<bool> &aFire) :
mNumber(aNumber),
mFire(aFire),
mStep(1){ }
void cChecker::operator ()()
{
while (true)
{
while (mFire.load()) std::this_thread::sleep_for(mMillisecond);
std::cout << "checker " << mNumber << " step " << mStep << "\n";
std::this_thread::sleep_for(mCheckDuration);
if (mStep % 20 == 1) mFire.store(true);
mStep++;
}
}
private:
static const std::chrono::milliseconds
mMillisecond,
mCheckDuration;
const size_t mNumber;
size_t mStep;
std::atomic<bool> &mFire;
};
const std::chrono::milliseconds
cChecker::mMillisecond(1),
cChecker::mCheckDuration(500);
void main()
{
std::atomic<bool> vFire(false);
std::atomic<size_t> vCouter(0);
std::thread vConsumerThreads[16];
for (size_t i = 0; i < 16; i++)
{
vConsumerThreads[i] = std::move(std::thread(cConsumer(i, 16, vFire, vCouter)));
}
std::chrono::milliseconds vNextCheckerDelay(239);
std::thread vCheckerThreads[3];
for (size_t i = 0; i < 3; i++)
{
vCheckerThreads[i] = std::move(std::thread(cChecker(i, vFire)));
std::this_thread::sleep_for(vNextCheckerDelay);
}
for (size_t i = 0; i < 16; i++) vConsumerThreads[i].join();
for (size_t i = 0; i < 3; i++) vCheckerThreads[i].join();
我认为存在更好的解决方案。
答案 0 :(得分:0)
运气不错,一旦你放火,可能会有更多的工人通过这条线:
while(!mFire.load()) std::this_thread::sleep_for(mMillisecond);
假设有10名工作人员醒着,那个计数器为0.每10名工人将执行此操作:
size_t vCounter = mCouter.fetch_add(1);
现在,10名工人中的每一名都有1到11之间的不同计数器。第5名将首先执行if子句:
if(vCounter < 5)
任何具有更高计数器的线程都将继续。其中第6个线程,将重置火并重置计数器:
if(vCounter == 5)
{
mFire.store(false);
mCouter.store(0);
cout << "RESET!!!!!! by consume "<<mNumber << endl; // useful to understand
}
所有这些谜题线程将继续循环等待下一次火灾。
但现在可能会发生不好的事情,因为你有一些工作人员还在工作,而且你有一堆跳棋等着再次放火:
while(mFire.load()) std::this_thread::sleep_for(mMillisecond);
... // now that fire is reset, they will go on
有些可以到达以下行:
if(mStep % 20 == 1) {
mFire.store(true);
cout << "SET FIRE" << endl; // to make the problem visual
}
当原子计数器为0时,除了仍在运行的工作之外,你将立即拥有5个新工作人员。
我不清楚你打算做什么:
您是否希望在任何时刻让最多5名工作人员活跃?在这种情况下,你永远不应该像你那样将工作器数量重置为0,但是你应该减少所有增加它的线程的计数器。因此,conter将包含当前在fire处理部分中的线程数:
while(true)
{
while(!mFire.load()) std::this_thread::sleep_for(mMillisecond);
size_t vCounter = mCouter.fetch_add(1); // FIRE PROCESSING: INCREMENT COUNTER
if(vCounter < 5)
{
std::cout << " FIRE! consumer " << mNumber << ", counter " << vCounter << "\n";
std::this_thread::sleep_for(mWorkDuration);
std::cout << " finished consumer "<< mNumber<<endl;
}
if(vCounter == 5)
{
mFire.store(false);
//mCouter.store(0);
cout << "RESET!!!!!! by consumer "<<mNumber << endl;
}
mCouter.fetch_sub(1); // END OF PROCESSING: DECREMENT COUNTER
答案 1 :(得分:0)
可能的解决方案是为消费者完成标志使用辅助数组。当消费者完成处理时,它将真实存储到其完成的阵列单元格。另一个控制线程扫描done数组,确保所有单元都为真,并重置程序状态。
#include <iostream>
#include <thread>
#include <atomic>
#include <chrono>
class cConsumer
{
public:
cConsumer::cConsumer(
const size_t aNumber,
const size_t aFiresLimit,
std::atomic<bool> &aFire,
std::atomic<bool> &aDone,
std::atomic<size_t> &aCounter) :
mNumber(aNumber),
mFiresLimit(aFiresLimit),
mFire(aFire),
mDone(aDone),
mCounter(aCounter){}
void cConsumer::operator ()()
{
while (true)
{
while (!mFire.load()) std::this_thread::sleep_for(mMillisecond);
const size_t vCounter = mCounter.fetch_add(1);
if (vCounter < mFiresLimit)
{
std::cout << " FIRE! consumer " << mNumber << ", counter " << vCounter << "\n";
std::this_thread::sleep_for(mWorkDuration); // instead real processing
}
mDone.store(true);
while (mDone.load()) std::this_thread::sleep_for(mMillisecond);
}
}
private:
static const std::chrono::milliseconds
mMillisecond,
mWorkDuration;
const size_t
mNumber,
mFiresLimit;
std::atomic<bool>
&mFire,
&mDone;
std::atomic<size_t> &mCounter;
};
const std::chrono::milliseconds
cConsumer::mMillisecond(1),
cConsumer::mWorkDuration(1300);
class cChecker
{
public:
cChecker(
const size_t aNumber,
std::atomic<bool> &aFire) :
mNumber(aNumber),
mFire(aFire),
mStep(1){ }
void cChecker::operator ()()
{
while (true)
{
while (mFire.load()) std::this_thread::sleep_for(mMillisecond);
std::cout << "checker " << mNumber << " step " << mStep << "\n";
std::this_thread::sleep_for(mCheckDuration);
if (mStep % 20 == 1) // dummy condition instead real checker function
{
mFire.store(true);
}
mStep++;
}
}
private:
static const std::chrono::milliseconds
mMillisecond,
mCheckDuration;
const size_t mNumber;
size_t mStep;
std::atomic<bool> &mFire;
};
const std::chrono::milliseconds
cChecker::mMillisecond(1),
cChecker::mCheckDuration(500);
class cController
{
public:
cController(
const size_t aConsumerCount,
std::atomic<bool> &aFire,
std::atomic<bool> * const aConsumersDone,
std::atomic<size_t> &aCounter) :
mConsumerCount(aConsumerCount),
mFire(aFire),
mConsumersDone(aConsumersDone),
mCounter(aCounter){}
void cController::operator ()()
{
while (true)
{
while(!mFire.load()) std::this_thread::sleep_for(mMillisecond);
bool vAllConsumersDone = false;
while (!vAllConsumersDone)
{
size_t i = 0;
while ((i < mConsumerCount) && (mConsumersDone[i].load())) i++;
vAllConsumersDone = (i == mConsumerCount);
std::this_thread::sleep_for(mMillisecond);
}
mFire.store(false);
for (size_t i = 0; i < mConsumerCount; i++) mConsumersDone[i].store(false);
mCounter.store(0);
}
}
private:
const size_t mConsumerCount;
static const std::chrono::milliseconds mMillisecond;
std::atomic<bool>
&mFire,
* const mConsumersDone;
std::atomic<size_t> &mCounter;
};
const std::chrono::milliseconds cController::mMillisecond(1);
void main()
{
static const size_t
vCheckerCount = 3,
vConsumersCount = 16,
vFiresLimit = 5;
std::atomic<bool> vFire(false);
std::atomic<bool> vConsumersDone[vConsumersCount];
for (size_t i = 0; i < vConsumersCount; i++) vConsumersDone[i].store(false);
std::atomic<size_t> vCounter(0);
std::thread vControllerThread(cController(vConsumersCount, vFire, vConsumersDone, vCounter));
std::thread vConsumerThreads[vConsumersCount];
for (size_t i = 0; i < vConsumersCount; i++)
{
vConsumerThreads[i] = std::move(std::thread(cConsumer(i, vFiresLimit, vFire, vConsumersDone[i], vCounter)));
}
std::chrono::milliseconds vNextCheckerDelay(239);
std::thread vCheckerThreads[vCheckerCount];
for (size_t i = 0; i < vCheckerCount; i++)
{
vCheckerThreads[i] = std::move(std::thread(cChecker(i, vFire)));
std::this_thread::sleep_for(vNextCheckerDelay);
}
for (size_t i = 0; i < vConsumersCount; i++) vConsumerThreads[i].join();
for (size_t i = 0; i < vCheckerCount; i++) vCheckerThreads[i].join();
vControllerThread.join();
}
输出(部分)示例:
...
checker 2 step 19
checker 1 step 19
checker 0 step 19
checker 2 step 20
checker 0 step 20
checker 1 step 20
checker 2 step 21
checker 0 step 21
checker 1 step 21
FIRE! consumer 11, counter 0
FIRE! consumer 3, counter 2
FIRE! consumer 4, counter 3
FIRE! consumer 10, counter 4
FIRE! consumer 14, counter 1
checker 0 step 22
checker 2 step 22
checker 1 step 22
checker 2 step 23
checker 0 step 23
checker 1 step 23
checker 2 step 24
checker 0 step 24