从Mysql创建嵌套数组

时间:2015-06-13 10:37:02

标签: php mysql json

我正在尝试从mysql获取正确的Json数据。我取得了很大的进步。看一看;

我有如下表:

name             folder    path
RayMala          787       01.jpg,02.jpg,03.jpg,04.jpg,05.jpg...
RayMala          788       01.jpg,02.jpg,03.jpg,04.jpg,05.jpg,06.jpg...
Falitiko         332       01.jpg...
Falitiko         333       01.jpg,02.jpg...

我的当前代码:从单个表格单元格制作数组。

$rows = array();
while($r = mysqli_fetch_assoc($result)) {   
    $rows[] = $r;
}

$nArray = array();
foreach($rows as $value){
    $nArray[] = array('name' => $value['name'], 'folder' => $value['folder'], 'path' => explode(",", $value['path']));
}

print json_encode($nArray);

当前JSON输出:请参阅名称值重复。

[
    {
        "name": "RayMala",
        "folder": "787",
        "Paths": ["1.jpg", "2.jpg", "3.jpg"]
    },
    {
        "name": "RayMala",
        "folder": "788",
        "Paths": ["1.jpg", "2.jpg", "3.jpg"]
    },
    {
        "name": "Falitiko",
        "folder": "333",
        "Paths": ["1.jpg", "2.jpg", "3.jpg"]
    }
]

通缉JSON输出:

[
    {
        "name":"RayMala",
        "random": [
            {
                "folder": "787",
                "Paths": ["1.jpg", "2.jpg", "3.jpg"]
            },
            {
                "folder": "788",
                "Paths": ["1.jpg", "2.jpg", "3.jpg"]
            }
        ]
    },
    {
        "name":"Falitiko",
        "random": [
            {
                "folder": "332",
                "Paths": ["1.jpg", "2.jpg", "3.jpg"]
            },
            {
                "folder": "333",
                "Paths": ["1.jpg", "2.jpg", "3.jpg"]
            }
        ]
    }
]

1 个答案:

答案 0 :(得分:2)

$nArray = array();
while($r = mysqli_fetch_assoc($result)) {   
   $nArray[$r["name"]][] = array('folder' => $r['folder'], 'path' => explode(",", $r['path']));
}
$output_arr = array();
foreach($nArray as $key=>$value){
   $output_arr[]=array("name"=>$key,"random"=>$value);
}
echo json_encode($output_arr);