在下面的代码中,我制作了一个程序,可以将您转入的金额转换为单词。例如," 1234.56"转入"一千二百三十四和...... 56美分"。问题是,当我尝试输入金额" 0.01"进入我的scanf
,输出变为"美元和...... 1美分"什么时候应该输出"零美元和... 1分"。请帮忙!
代码如下:
#include <stdio.h>
void printNum(int);
void printNum2(int);
int main()
{
int a = 0;
int b = 0;
int c = 0;
int d = 0;
int num = 0;
int printcents; //To convert the float "cents" to an integer.
float inclusive;
float cents;
printf("Welcome to the IPC144 Cheque Generator!!\n");
printf("PAY TO THE ORDER OF... amahmood29 (018359133)\n");
printf("Enter a monetary value from $0.01 to $9999.99 inclusive: ");
scanf("%f", &inclusive);
if(inclusive < 0.00 || inclusive >= 10000.00) {
printf("Sorry, cannot create cheque for that amount, try again next time!\n");
}
else
{
a = inclusive / 1000; //This data is replacing our variable by diving whatever the vaulue is by either 1000, 100, 10.
inclusive = inclusive - (a*1000);
b = inclusive / 100;
inclusive = inclusive - (b*100);
if ( inclusive > 19 ){
c = inclusive / 10;
inclusive = inclusive - (c*10);
}
else
{
c = inclusive;
d = 0;
}
d = inclusive;
num = inclusive;
cents = (inclusive - num)*100; //To calculate our "Cents" with numerals.
printcents = cents;
/*Printing if the variables are in the thousands, hundreds, tens or ones categories.*/
if (a > 0){
printNum(a);
printf("Thousand ");
}
if (b > 0){
printNum(b);
printf("Hundred ");
}
printNum2(c);
if (d >= 0){
printNum(d);
printf("Dollars and ... ");
}
else if (c == 0 && b == 0 && a == 0){
printf("Zero Dollars and ... ");
}
printf("%d", printcents);
printf(" Cents\n");
}
}
void printNum(int x) //Created functions to easily output various if statements.
{
if ( x == 1)
printf("One ");
else if ( x == 2)
printf("Two ");
else if (x == 3)
printf("Three ");
else if (x == 4)
printf("Four ");
else if (x == 5)
printf("Five ");
else if (x == 6)
printf("Six ");
else if (x == 7)
printf("Seven ");
else if (x == 8)
printf("Eight ");
else if (x == 9)
printf("Nine ");
}
void printNum2(int x)
{
if ( x == 10)
printf("Ten ");
else if ( x == 11)
printf("Eleven ");
else if ( x == 12)
printf("Twelve ");
else if ( x == 13)
printf("Thirteen ");
else if (x == 14)
printf("Fourteen ");
else if (x == 15)
printf("Fifteen ");
else if (x == 16)
printf("Sixteen ");
else if (x == 17)
printf("Seventeen ");
else if (x == 18)
printf("Eighteen ");
else if (x == 19)
printf("Nineteen ");
else if (x == 2)
printf("Twenty ");
else if (x == 3)
printf("Thirty ");
else if (x == 4)
printf("Forty ");
else if (x == 5)
printf("Fifty ");
else if (x == 6)
printf("Sixty ");
else if (x == 7)
printf("Seventy ");
else if (x == 8)
printf("Eighty ");
else if (x == 9)
printf("Ninety ");
}
答案 0 :(得分:1)
您可以使用嵌套的if else
。首先检查它是否为零美元,否则执行您的过程。尝试这样的事情:
if (c == 0 && b == 0 && a == 0){
printf("Zero Dollars and ... ");
}
else{
if (a > 0){
printNum(a);
printf("Thousand ");
}
if (b > 0){
printNum(b);
printf("Hundred ");
}
printNum2(c);
if (d >= 0){
printNum(d);
printf("Dollars and ... ");
}
}
而不是
if (a > 0){
printNum(a);
printf("Thousand ");
}
if (b > 0){
printNum(b);
printf("Hundred ");
}
printNum2(c);
if (d >= 0){
printNum(d);
printf("Dollars and ... ");
}
else if (c == 0 && b == 0 && a == 0){
printf("Zero Dollars and ... ");
在if(d>=0)
满足的代码中,如果以前的任何语句都为真,它将永远不会输入else if
语句(else if
跳过。)
答案 1 :(得分:0)
很快看,但是:
# .bash_profile
# Get the aliases and functions if [ -f ~/.bashrc ]; then
. ~/.bashrc fi
# User specific environment and startup programs
PATH=$PATH:$HOME/bin export PATH=$PATH:/usr/local/bin:/usr/local/sbin:/opt/FriendlyARM/toolschain/4.5.1/bin/arm-linux-g++:/usr/bin/gmake:/usr/share/bin:/usr/share/sbin
再次,这是一个快速的外观,我没有测试它。